It is 36.
You have to make your unlike denominators to like. Do that by finding the common factor for each set of fractions. Remember, that what you do with the numerator you do with the denominator ( lets say you want to add 1/2 + 2/4)( divide or multi by the same factor) 1/2 = 1 x2= 2 this makes 2/4 and now you can add 2/4 + 1/4= 3/4 2 x2=4 Hope this helps. It hard to explain online like this.
The two numbers are x2 - x and 8x - 4. The least common multiple is the product of the numbers divided by their greatest common factor. For this example, I will assume that x is a positive integer > 1, since otherwise x2-x = 0, and the least common multiple would then be 0. So, the next step is to determine the greatest common factor. To do that, factor each of the numbers. These numbers can be rewritten as x(x-1) and 4(2x-1). The factors of x2 - x are x and x-1. The factors of 8x - 4 are 2, 2, and 2x-1. Neither x nor x-1 evenly divide 2x-1. However, either x or x-1 is even, which means one of them is divisible by 2. Since 2 is a factor of 8x-4, the greatest common factor is at least 2, but since we do not know the value of x, the greatest common factor might be 4. So, the least common multiple is either (x2-x)(8x-4)/2 = (8x3-12x2-4x)/2 = 4x3-6x2-2x or (x2-x)(8x-4)/4 = (8x3-12x2-4x)/4 = 2x3-3x2-x.
Subtract them. example: x3 --- x1 Subtract the 1 from the 3 and you get x2 over 1 or just x2
2 to the third power x2=highest common factor of 100 and 96=16
x2 + x2 = 2x2
3x2
3x2 has x, x2 , and 3 as factors. 2x-5 does not have any of those as factors. So the greatest common factor is 1. If you were adding rational expressions with those two expressions in the denominator, you would need to multiply them together to find the least common denominator.
x2 + 2x
Not necessarily. The denominator need not have any real zeros, for example x2+1. Not necessarily. The denominator need not have any real zeros, for example x2+1. Not necessarily. The denominator need not have any real zeros, for example x2+1. Not necessarily. The denominator need not have any real zeros, for example x2+1.
Since x2 - 1 is a multiple of x - 1, it is the LCM of this problem.
6
Their product.
x2 - 4
x2 - x - 12First try and factor that expression.Notice that it happens to be the product of (x - 4) and (x + 3). This makes your problem easy.(x2 - x - 12) / (x - 4)= (x - 4) (x + 3) / (x - 4)Now just divide numerator and denominator by the common factor. ("Cancel" (x - 4) out of numerator and denominator.)Wind up with the answer = (x + 3)
You have to make your unlike denominators to like. Do that by finding the common factor for each set of fractions. Remember, that what you do with the numerator you do with the denominator ( lets say you want to add 1/2 + 2/4)( divide or multi by the same factor) 1/2 = 1 x2= 2 this makes 2/4 and now you can add 2/4 + 1/4= 3/4 2 x2=4 Hope this helps. It hard to explain online like this.
2x / (x2) = 2*x / (x*x); cancel an x from numerator & denominator: 2 / x
Grammar in mathematics is important so that the question cannot be misunderstood. The question is asking for the solution to 1/(x + 8) + 6/(x - 8). Where fractions are being added or subtracted then the denominators need converting to a common denominator. With numbers this new denominator would be the Lowest Common Multiple. With algebraic terms then simply take the product. The common multiple of (x + 8) and (x - 8) is (x + 8)(x - 8) = x2 - 82 1/(x + 8) = 1 x (x - 8)/x2 - 82 = x - 8/x2 - 82 6/(x - 8) = 6 x (x + 8)/x2 - 82 = 6x + 48/x2 - 82 1/(x + 8) + 6/(x - 8) = x - 8/x2 - 82 + 6x + 48/x2 - 82 = 7x + 40/x2 - 82