Best Answer

x=0 and y=4 or;

x=0 and y=-4 or;

x=4 and y=0 or;

x=-4 and y=0 all are solutions

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First, you need to understand clearly what "solve" means.

The "solution" to an equation normally means a set of numerical values for all

of the variables that appear in it, that makes the equation a true statement.

In order to find a solution, you generally need the same number of different

equations as there are variables in them. That is, if the equation has both

'x' and 'y' in it, then you need two different facts about their relationship in

order to figure out what numbers they are.

When you graph the equation in the question ... x2+ y2 = 16 ... the graph is

a circle, with its center at the origin, and with a radius of 4. Every point on that

circle has 'x' and 'y' coordinates, and every point is a solution to the equation.

So, just as it stands, there are an infinite number of "solutions".

Q: What is x and y if x squared plus y squared equals 16?

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16

30 squared is 900. 16 squared 256. add them and you get 1156. Now, simply do: √1156 The answer is 34. Its simple: (30•30)+(16•16)=x^2 900+256=x^2 1156=x^2 √1156=x 34=x

2(x - 2)(x - 4)

89

Solve using the quadratic formula

Related questions

16

(x + 4)(x +4) or (x + 4)squared

30 squared is 900. 16 squared 256. add them and you get 1156. Now, simply do: √1156 The answer is 34. Its simple: (30•30)+(16•16)=x^2 900+256=x^2 1156=x^2 √1156=x 34=x

X = √63

2(x - 2)(x - 4)

89

You are describing a circle, with its center at the origin and a radius of 4 (the square root of 16)

Solve using the quadratic formula

32 + x = 259 + x = 25x = 25 - 9x = 16

{-1,7}

2 squared plus 2 x 3 = 10, 7 squared plus 7 x 2 = 63, 6 squared plus 6 x 5 = 66,8 squared plus 8 x 4 = 96 so 9 squared plus 9 x 7 = 81 + 63 = 144.

x2 (4x4=16) + Y2 (4x4=16) = 32 You normally would leave out the bracketed bits but to simplify the equation. Cheers.