3x = 70 x = 70/3 or 23 and 1/3
3X+70-7*18=0 3X+70-126=0 3X-56=0 3X=56 x=56/3 or 18.6667
3x = 70 70/3 = x Therefore, x = 23.3 recurring (that is, 23.3333..)
3X - 4 = 66 add 4 to each side 3X - 4 + 4 = 66 + 4 3X = 70 divide each sides integers by 3 (3/3)X = 70/3 X = 70/3 ------------------check in original equation 3(70/3) - 4 = 66 210/3 - 4 = 66 70 - 4 = 66 66 = 66 ---------------checks ( naturally, you could have canceled here, 3(70/3) and just got 70 )
x - 2x + 10 + 4x = 70 Combine like terms: 3x + 10 = 70 Subtract 10 from both sides: 3x = 60 Divided both sides by 3: x = 20
3x = 70 x = 70/3 or 23 and 1/3
3X+70-7*18=0 3X+70-126=0 3X-56=0 3X=56 x=56/3 or 18.6667
3x = 70 70/3 = x Therefore, x = 23.3 recurring (that is, 23.3333..)
x(2+3)-70 5x-70 70/5= x-14
3X - 4 = 66 add 4 to each side 3X - 4 + 4 = 66 + 4 3X = 70 divide each sides integers by 3 (3/3)X = 70/3 X = 70/3 ------------------check in original equation 3(70/3) - 4 = 66 210/3 - 4 = 66 70 - 4 = 66 66 = 66 ---------------checks ( naturally, you could have canceled here, 3(70/3) and just got 70 )
x - 2x + 10 + 4x = 70 Combine like terms: 3x + 10 = 70 Subtract 10 from both sides: 3x = 60 Divided both sides by 3: x = 20
3x * (x - 4) = 3x*x - 3x*4 = 3x^2 - 12x.
- 3x - Xsame as- 3x + (- X)= - 4X=====
Let the first even number be x. Then the second even number would be x + 2, and the third even number would be x + 4. The sum of these numbers is x + (x + 2) + (x + 4) = 3x + 6. We set this equal to 204 and solve for x: 3x + 6 = 204 --> 3x = 198 --> x = 66. Therefore, the three consecutive even numbers are 66, 68, and 70.
(3x2 - 6x)/3x = 3x(x-2)/3x = x-2, for x<>0
3x * (x - 4) = 3x*x - 3x*4 = 3x^2 - 12x.
x^2 + 3x + 2/(-3x) - x^2 - 2=3x-2+2/(-3x)=3x-2-2/(3x)