logx=12
x=10^12
x=1,000,000,000,000
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(12)2x = 28(2x) log(12) = log(28)2x = log(28) / log(12) = 1.34098 (rounded)x = 0.67049 (rounded)
5x 12x = 17xx log(5) + x log(12) = x log(17)x [ log(5) + log(12) ] = x log(17)x log(60) = x log(17)x = 0This actually checks. Since anything to the zero power is ' 1 ',50 120 = 1 times 1, or 1and 170 = 1
log x = -4 => x = 10-4 = 0.0001
log(x) = 3x = 10log(x) = 103 = 1,000
0.4772