(12)2x = 28(2x) log(12) = log(28)2x = log(28) / log(12) = 1.34098 (rounded)x = 0.67049 (rounded)
5x 12x = 17xx log(5) + x log(12) = x log(17)x [ log(5) + log(12) ] = x log(17)x log(60) = x log(17)x = 0This actually checks. Since anything to the zero power is ' 1 ',50 120 = 1 times 1, or 1and 170 = 1
log x = -4 => x = 10-4 = 0.0001
log(x) = 3x = 10log(x) = 103 = 1,000
0.4772
(12)2x = 28(2x) log(12) = log(28)2x = log(28) / log(12) = 1.34098 (rounded)x = 0.67049 (rounded)
5x 12x = 17xx log(5) + x log(12) = x log(17)x [ log(5) + log(12) ] = x log(17)x log(60) = x log(17)x = 0This actually checks. Since anything to the zero power is ' 1 ',50 120 = 1 times 1, or 1and 170 = 1
If the log of x equals -3 then x = 10-3 or 0.001or 1/1000.
the value of log (log4(log4x)))=1 then x=
y = 10 y = log x (the base of the log is 10, common logarithm) 10 = log x so that, 10^10 = x 10,000,000,000 = x
log x = -4 => x = 10-4 = 0.0001
log(x) = 3x = 10log(x) = 103 = 1,000
log x2 = 2 is the same as 2 log x = 2 (from the properties of logarithms), and this is true for x = 10, because log x2 = 2 2 log x = 2 log x = 1 log10 x = 1 x = 101 x = 10 (check)
log(x) + log(2) = log(2)Subtract log(2) from each side:log(x) = 0x = 100 = 1
log(10) 12 = 1.07918 Then the antilog is 12 = 10^(1.07918) You must specify the base to which to logarithm is functioning. Different log bases will give different answers.
0.4772
"Log" is not a normal variable, it stands for the logarithm function.log (a.b)=log a+log blog(a/b)=log a-log blog (a)^n= n log a