(x + y)3 + (x - y)3 = (x3 + 3x2y + 3xy2 + y3) + (x3 - 3x2y + 3xy2 - y3) = 2x3 + 6xy2 = 2x*(x2 + 3y2)
y*x8
X + Y⁶X + Y * Y * Y * Y * Y * Y
The degree is 5.
xy 2nd
(x + y)3 + (x - y)3 = (x3 + 3x2y + 3xy2 + y3) + (x3 - 3x2y + 3xy2 - y3) = 2x3 + 6xy2 = 2x*(x2 + 3y2)
999 and 1
(x+y)power 2 -2xy
y*x8
X + Y⁶X + Y * Y * Y * Y * Y * Y
15
That would be very hard to answer, because it's not. (x + y)2 = x2 + y2 + 2xy
The degree is 5.
0
xy 2nd
Y = ex(x + 2) Y = ex/(X + 2) =========
No, to be linear, both the power of x and y need to be 1. Since x is squared, the power of x is 2.