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Q: X to the power of 2 plus y to the power of 2?

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999 and 1

xy plus 2x plus 4y plus 8 or (xy+2x) + (4y+8) or x(y+2) + 4(y+2) or (x+4)(y+2)

It is difficult to tell because this site uses a useless browser: one which cannot accept most mathematical symbols. So all we can see of the given equation is "y x2 10x plus 30", and the options appear as "y (x 5)2 plus 55 y (x 5)2 plus 30 y (x 5)2 5 y (x 5)2 plus 5".If the equation is y = x^2 - 10x + 30 then the answer is y = (x - 5) ^2 + 5.

(x+y)4 = (x2+2xy+y2)2 = x4+4x3y+6x2y2+4xy3+y4

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The degree is 5.

Y = ex(x + 2) Y = ex/(X + 2) =========

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That would be very hard to answer, because it's not. (x + y)2 = x2 + y2 + 2xy

No, to be linear, both the power of x and y need to be 1. Since x is squared, the power of x is 2.

999 and 1

(x+y)^2+z^2=x^2+y^2+z^2+2xy or ((x+y)^2+z)^2= (x^2+y^2+2xy+z)^2= x^4+y^4+z^2+6x^2y^2+4x^3y+2x^2z^2+4xy^3+4xyz^2+2z^2y^2

X power 2 (X power 2 - 10) and Y power 2 (1+9)

5x + 3y - 2 - x + y + 2 = 4x + 4y = 4(x + y)

If: x+2 = y+6 Then: y = x-4

x^3+y^3 Cube root of the first, x plus cube root of the last, y times What it takes to make the first number, x^2 Opposite sign, - Product of the two cube roots, -xy Then what it takes to make the last. (x+y)(X^2-xy+y^2)

Only when X or Y = 0 That is because (x + y) squared = x^2 + 2xy + y^2 x^2 + 2xy + y^2 = x^2 + y^2 when x or y = 0

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