The only thing you can do is to rewrite it as x(x + 20). For anything else, you need the value of x.
They touch each other at (0, 100) on the x and y axis.
x(x - 19)(x - 1)
The value of such an expression depends on the values assigned to the variables, in this case, x and c.
5x2 + 20x = 5x (x + 4)
20x + 5 - 20 = 21x + 4 -x = 4 + 15 x = -19
5x2 + 20x = 0 5x(x + 4) = 0 x = 0 and -4
The graphs of the two equations will intersect when x² + 20x + 100 = y = x² - 20x + 100 Subtracting x² +100 from both sides you get 20x = -20x that will only be true when x = 0. At x = 0, y = 100 for both equations - so the point of contact would be (0,100)
They touch each other at (0, 100) on the x and y axis.
5(x + 3)(x + 1)
x(x - 19)(x - 1)
The value of such an expression depends on the values assigned to the variables, in this case, x and c.
x2 + 9x2 = 10x2
Combine all lie term: x + x - 22x = -20x 2 + 1 = 3 So the answer is -20x +3 or 3 - 20x
x2-20x+100 = (x-10)(x-10) when factored
5x2 + 20x = 5x (x + 4)
( x^2 + 10x )^2 = ( x^2 + 10 x) ( x^2 + 10x ) = x^4 + 10x^3 + 10x^3 + 100x^2 = x^4 + 20x^3 + 100x^2 <----------------
If: y = 10x -12 and y = x^2 +20x +12 Then: x^2 +20x +12 = 10x -12 Transposing terms: x^2 +10x +24 = 0 Factorizing: (x+6)(x+4) = 0 => x = -6 or x = -4 Points of intersection by substitution are at: (-6, -72) and (-4, -52)