The value of such an expression depends on the values assigned to the variables, in this case, x and c.
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They touch each other at (0, 100) on the x and y axis.
x(x - 19)(x - 1)
The only thing you can do is to rewrite it as x(x + 20). For anything else, you need the value of x.
C2x + C2y = C2(x + y)
5x2 + 20x = 5x (x + 4)