They touch each other at (0, 100) on the x and y axis.
x(x - 19)(x - 1)
The only thing you can do is to rewrite it as x(x + 20). For anything else, you need the value of x.
C2x + C2y = C2(x + y)
5x2 + 20x = 5x (x + 4)
x2 + 9x2 = 10x2
5x2 + 20x = 0 5x(x + 4) = 0 x = 0 and -4
The graphs of the two equations will intersect when x² + 20x + 100 = y = x² - 20x + 100 Subtracting x² +100 from both sides you get 20x = -20x that will only be true when x = 0. At x = 0, y = 100 for both equations - so the point of contact would be (0,100)
5(x + 3)(x + 1)
They touch each other at (0, 100) on the x and y axis.
x(x - 19)(x - 1)
The only thing you can do is to rewrite it as x(x + 20). For anything else, you need the value of x.
C2x + C2y = C2(x + y)
Combine all lie term: x + x - 22x = -20x 2 + 1 = 3 So the answer is -20x +3 or 3 - 20x
This is the common form of the Pythagorean Theorem. It describes the relationship between the two legs of a right triangle and the hypotenuse.
x^2+10*x+2.99792e+08
x2-20x+100 = (x-10)(x-10) when factored