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What is the equation of sphere?
The equation of a sphere with radius r, centered at (x0 ,y0 ,z0 ) is (x-x0 )+(y-y0 )+(z-z0 )=r2
What is 4x to the third and y to the zero?
(4x)3 = 64x3 y0 = 1
What is the angle between the two lines x0 and y0?
x0 and y0 aren't lines. Do you mean x=0 and y=0? If so, they are the y axis and the x axis, respectively, and the answer is 90 degrees as noted above.
How to calculate year over year percentage?
Suppose the value of some quuantity Y, in year 0 was Y0. Suppose the following year, it was Y1. Then year over year percantage change is = 100*(Y1/Y0 -1).
What is x-y0 and 7x-3y24?
If you mean: x -y = 0 and 7x -3y = 24 then they are simultaneous equations whose solutions are x = 6 and y = 6
Equation for linear approximation?
The general equation for a linear approximation is f(x) ≈ f(x0) + f'(x0)(x-x0) where f(x0) is the value of the function at x0 and f'(x0) is the derivative at x0. This describes a tangent line used to approximate the function. In higher order functions, the same concept can be applied. f(x,y) ≈ f(x0,y0) + fx(x0,y0)(x-x0) + fy(x0,y0)(y-y0) where f(x0,y0) is the value of the function at (x0,y0), fx(x0,y0) is the partial derivative with respect to x at (x0,y0), and fy(x0,y0) is the partial derivative with respect to y at (x0,y0). This describes a tangent plane used to approximate a surface.
Does y0 represent y as a function of x?
y0(x) could represent a function of x but usually y(0) represents the function y that is evaluated at x = 0 and so is no longer a function of x but a constant.
What is the equation of sphere?
The equation of a sphere with radius r, centered at (x0 ,y0 ,z0 ) is (x-x0 )+(y-y0 )+(z-z0 )=r2
What is 4x to the third and y to the zero?
(4x)3 = 64x3 y0 = 1
What are slope-intercept and point-slope forms please show examples?
Slope-intercept is: y = mx + c where m = slope; and c = intercept. Example y = 3x + 5 slope = 3 intercept = 5 Point-slope is: y - y0 = m(x - x0) where m = slope; point (x0, y0) is a point on the line. Example y - 8 = 3(x - 1) slope = 3 point (1, 8) is on the line. The two are interchangeable: y - y0 = m(x - x0) → y - y0 = mx - mx0 → y = mx + (y0 - mx0) Which means that y0 - mx0 = c, the intercept. Example: y - 8 = 3(x - 1) → y = 3x + (8 - 3×1) → y = 3x + 5 → the two examples above are the same line in different forms.
If the slope of a line is already known what else is needed in order to create an equation?
Either a point or the y-intercept.If the y-intercept is known (call it b), and, calling the slope m, the equation is y = mx + b.If a sample point (x0, y0) is known, then the equation is y - y0 = m(x - x0).
What is the angle between the two lines x0 and y0?
x0 and y0 aren't lines. Do you mean x=0 and y=0? If so, they are the y axis and the x axis, respectively, and the answer is 90 degrees as noted above.
Which equation represents the line that passes through points (1 5) and (3 17)?
The general equation of a line through point (x0, y0) with gradient m is given by: y - y0 = m(x - x0) The gradient m between two points (x0, y0) and (yx1, y1) is given by: m = change_in_y/change_in_x = (y1 - y0)/(x1 - x0) → line through points (1, 5) and (3, 17) is given by: y - 5 = ((17 - 5)/(3 - 1))(x - 1) → y - 5 = (12/2)(x - 1) → y - 5 = 6(x - 1) → y - 5 = 6x - 6 → y = 6x - 1
Is y0 a linear equation?
Hard to tell because of problems with the browser. If the question is about "y = 0" the answer is YES.
Code in c to draw line?
// macros for simplicity #define MAX(x,y) (x>y?x:y) #define MIN(x,y) (x<y?x:y) /* ** drawLine ** ** Draw a line from vertex (x0,y0) to vertex (x1,y1) using ** the midpoint line algorithm, implemented using OpenGL. ** */ void drawLine( GLint x0, GLint y0, GLint x1, GLint y1 ) {GLint dE, dNE, x, y, d, dx, dy; // check if we need to switch the points if( x0 > x1 ) { x0 = x0 + x1; x1 = x0 - x1; x0 = x0 - x1; y0 = y0 + y1; y1 = y0 - y1; y0 = y0 - y1;} // calculate deltas dy = y1 - y0; dx = x1 - x0; // special cases if( dx -1 - diag down-right glBegin(GL_POINTS); for( x = x0, y = y0; x <= x1; x++, y-- ) { glVertex2i(x,y);} glEnd();}else { // general cases // midpoint algorithm if( abs(dy) < dx ) { // small slope dE = 2 * abs(dy); dNE = 2 * (abs(dy) - dx); d = dE - dx; glBegin(GL_POINTS); for( x = x0, y = y0; x <= x1; x++ ) { glVertex2i(x,y); if( d <= 0 ) { d+= dE;}else { y += (dy>0?1:-1); d += dNE;}}// for x = x0 to x1 glEnd();}else { // large slope dE = 2 * dx; dNE = 2 * (dx - abs(dy)); d = dE - abs(dy); glBegin(GL_POINTS); for( x = x0, y = y0; (y0 < y1 && y <= y1) (y0 > y1 && y >= y1); y+=(y0 < y1?1:-1) ) { glVertex2i(x,y); if( d <= 0) { x ++; d+= dE; }else { d += dNE; }}// for y = y0 to y1 glEnd();}} }// drawLine()
Which circles lie completely within the fourth quadrant?
Circles that lie completely within the fourth quadrant of the Cartesian plane have their centers in the fourth quadrant and have a radius smaller than the distance from the center to the x-axis and y-axis. In other words, the circle's center coordinates (x, y) must both be positive, and the radius r must be less than both x and y. This ensures that the entire circle falls within the boundaries of the fourth quadrant.
How to calculate year over year percentage?
Suppose the value of some quuantity Y, in year 0 was Y0. Suppose the following year, it was Y1. Then year over year percantage change is = 100*(Y1/Y0 -1).
