The general equation of a line through point (x0, y0) with gradient m is given by:
y - y0 = m(x - x0)
The gradient m between two points (x0, y0) and (yx1, y1) is given by:
m = change_in_y/change_in_x = (y1 - y0)/(x1 - x0)
→ line through points (1, 5) and (3, 17) is given by:
y - 5 = ((17 - 5)/(3 - 1))(x - 1)
→ y - 5 = (12/2)(x - 1)
→ y - 5 = 6(x - 1)
→ y - 5 = 6x - 6
→ y = 6x - 1
Points: (6, -3) and (-4, -9) Slope: 3/5 Equation: 5y = 3x-33
Write the equation of the line that passes through the points (3, -5) and (-4, -5)
Y= -3x + 8
Points: (2, 5) and (4, 3) Slope: -1 Equation: y = -x+7
Points: (-1, 7) and (-2, 3) Slope: 4 Equation: y = 4x+11
Points: (6, -3) and (-4, -9) Slope: 3/5 Equation: 5y = 3x-33
Points: (6, -3) and (-4, -9) Slope: 3/5 Equation: 5y = 3x-33
Write the equation of the line that passes through the points (3, -5) and (-4, -5)
If you mean points of (2, -2) and (-4, 22) then the equation is y = -4x+6
The equation for the given points is y = x+4 in slope intercept form
It is y = 2.
Y= -3x + 8
Plug both points into the equation of a line, y =m*x + b and then solve the system of equations for m and b to get equation of the line through the points.
In order to find the equation of a tangent line you must take the derivative of the original equation and then find the points that it passes through.
If you mean points of (-4, 2) and (4, -2) Then the straight line equation works out as 2y = -x
Points: (0. 5) and (2, 3) Slope: -1 Equation: y = -x+5
Answer this question…y = 2x + 6