72
y2 * y-5 = y2 / y5 = 1/y3
Y3
30
y=3 y^3(y^3-y)= 3^3(3^3-3)= 27(27-3)= 27(24)=648
y times y times y (or y3)
y times y times y
y5 * y3 * y = y5 * y3 * y1 = y5+3+1 = y9
y4 times y3 = y7
72
The GCF of y3, y7, y8 is y3
In mathematics, the notation "y3" typically represents the cube of the variable "y," which is equivalent to y * y * y. This is a shorthand way of denoting the result of multiplying y by itself three times. The cube of a number is the number raised to the power of 3.
I assume you mean 2 times y times y times y. Since y is multiplied by itself three times, you have 2 times y3, also known as 2 times y cubed, which is written as 2y3.
y3 x y3 - y (3)3 x 3(3) - 3 9 x 9 - 3 = ? 9 x 9= 81 81 - 3 = 78 I hope that solves your problem
y2 * y-5 = y2 / y5 = 1/y3
Y3
y(y - 2)(y + 2)