It is the equation of a quadratic function that happens to factor very nicely:
y = 2x2 + 5x - 3 = (x + 3)(2x - 1).
When the product of two numbers equals zero, then one or other of them must equal zero.
Therefore, when y = 0, one of the two factors must also equal zero:
Hence, either x = -3 or x = ½, when y = 0.
This implies that the graph of this function crosses the x-axis at two places: namely, at (0,-3) and at (0,½).
As the graph of every quadratic function is a parabola, its axis of symmetry is the vertical line passing through the point on the x-axis that is mid-way betwixt the two points named above, where the function crosses the x-axis: namely, at (0,-1¼).
To find the vertex of the above parabola, we solve for y where x = -1¼:
y = (x + 3)(2x - 1)
= (-1¼ + 3)(-1¼ - 1)
= (1¾)(-2¼)
= (7/4)(-9/4) = 63/16 = 3 15/16
-3;
hence, the vertex is located at the point, (-1¼,315/16).
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No.
y = 5x3 + 6 is a cubic equation, not a linear equation. Linear equations contain only terms of degree 0 (i.e. constants) and terms of degree 1.
2x2 + 3x - 20 = (x + 4)(2x - 5).
no
y = 5x3 + 5 is a cubic equation. You cannot solve for x (or y), because there are two variables and only one equation. If you graph this, however, you will see a curve that passes through all possible points that make this equality true.