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What maximum height will be reached by a stone thrown straight up with an initial speed of 35 m's?
Wiki User
∙ 13y ago
s= vt+1/2gt^2
v2 = v02 + 2gs
0 = 352 - 2*9.8*s (taking down as the positive direction)
62.5 meters
Wiki User
∙ 13y ago
Andile Frank
63
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How is it that A ball is projected straight up from the ground with a speed of 7.61 meters per second To what maximum height will the ball go when gravity equals 9.80 meters per second squared?
Initial upward speed = 7.61 m/sFinal upward speed (at the point of maximum height) = 0Time to reach maximum height = (7.61) / (9.8) = 0.77653 secondAverage speed during that time = 1/2 ( 7.61 + 0) = 3.805 m/sHeight = 3.805 x 0.77653 = 2.9547 meters (rounded) = about 9.7 feetDoesn't seem like much of a height for a strong toss; but the math looks OK.
If the launch angle is 15 degrees and the initial velocity is 50.0 meters per second what is the range?
If the initial velocity is 50 meters per second and the launch angle is 15 degrees what is the maximum height? Explain.
How high does a ball go if it is thrown up with an initial speed of 10 meters per second?
applying the equation: (VxV) -(UXU) = 2aS on reaching the maximum height the ball stops so the final velocity(V) becomes =0. initial velocity as given is (U)=10 m/s. ------------------------------------------------------------------------------------2 acceleration is here gravity in downward direction so (a)=-9.81 m/s so applying the above stated formula the height reached by the ball(S)=5.0968 m (approx)
A long jumper leaves the ground at an angle 20 to horizontal and at speed of 11ms.how far does he jump and what the maximum height reached?
Making the improbable assumption that the jumper experiences no air resistance, he will jump 3.97 metres, and reach a height of 0.72 metres.
When throwing a ball straight up when in the air with an initial velocity of 10 meters per second what will be it maximum height?
'Maximum height' means the exact point at which the velocity changes from upward to downward. At that exact point, the magnitude of the velocity is zero. It doesn't matter what the velocity was when it left your hand. That number determines the maximum height, but the velocity at that height is always zero. --------------------------------------------------------- Thus using the formula: (vf)e2 = (vi)e2+2*a*d vf = final velocity = 0 m/s vi = initial velocity = 10 m/s a = acceleration = gravity = - 9.81 m/s/s d = displacement (distance) = ? e is designating that the next figure is an exponent in the formula So the formula is: (0)e2 = (10)e2 + (2 * -9.81 * d) 0 = 100 + -19.62d adding 19.62d to both sides of the equation 19.62d = 100 dividing by 19.62 d = ~ 5.097 meters
What relationship exists between the initial velocity and the maximum height reached by an object thrown upward?
Ignoring air resistance, I get this formula:Maximum height of a vertically-launched object = 1.5 square of initial speed/GI could be wrong. In that case, the unused portion of my fee will be cheerfully refunded.
When a ball is throw upward how does the height reached by the ball depend on its initial speed?
The height reached by a ball thrown upward depends on its initial speed: the higher the initial speed, the higher the maximum height reached. This is because a greater initial speed gives the ball more kinetic energy, allowing it to overcome gravity and reach a higher position before gravity brings it back down.
A boy kicks a ball vertically upwards with an initial velocity of 12m/s. Calculate the time taken by the ball to reach the maximum hight and the maximum, height reached by the ball?
The time taken by the ball to reach the maximum height is 1 second. The maximum height reached by the ball is 36 meters.
What is the maximum height achieved if a 0.800kg mass is thrown straight up with an initial speed of 30.0Ms-1?
The maximum height reached can be calculated using the formula h = (v^2) / (2g), where v is the initial velocity and g is the acceleration due to gravity (9.81 m/s^2). Plugging in the values gives h = (30^2) / (2*9.81) = 45.9 meters.
What is A football kicked off at an angle 20 from the ground reaches a maximum height of 4.7 m What is the initial velocity of the kick?
To find the initial velocity of the kick, you can use the equation for projectile motion. The maximum height reached by the football is related to the initial vertical velocity component. By using trigonometric functions, you can determine the initial vertical velocity component and then calculate the initial velocity of the kick.
When a football kicked reaches its maximum height how does its speed compare to its initial speed?
When it's at its maximum height its speed will be zero.
What is the maximum height reached by a wave from its rest position?
The maximum height reached by a wave from its rest position is called the amplitude. It is the distance from the rest position to the highest point of the wave.
What is the equation to calculate the maximum height of an object given an initial velocity and initial launch height?
height=acceletation(t^2) + velocity(t) + initial height take (T final - T initial) /2 and place it in for time and there you go
A ball is thrown straight up into the air at 25.5m/s. (Assume g = -9.8m/s2) A) How high did it go, in other words what is the maximum height reached by the objectB) On its way up, how long did it take to reach the maximum height?
265
How does angle of projection affect the maximum height?
The angle of projection affects the maximum height by determining the vertical and horizontal components of the initial velocity. At 90 degrees (vertical), all the initial velocity is vertical which results in maximum height. As the angle decreases from 90 degrees, the vertical component decreases, leading to a lower maximum height.
The velocity of a body thrown vertically upward is reduced into half in one secondwhat is the maximum height attained by it?
The maximum height attained by the body can be calculated using the formula: height = (initial velocity)^2 / (2 * acceleration due to gravity). Since the velocity is reduced to half in one second, we can calculate the initial velocity using the fact that the acceleration due to gravity is -9.81 m/s^2. Then, we can plug this initial velocity into the formula to find the maximum height reached.
If the initial speed of a projectile is doubled?
If the initial speed of a projectile is doubled, the projectile will have four times the kinetic energy compared to its initial state. This is because kinetic energy is proportional to the square of the velocity. The maximum height reached by the projectile will also be higher, as it will have more energy to overcome gravity.
