There is no four digit number where the ones is twice the tens, the hundreds is five less than the ones, and the thousands is the sum of the tens and hundreds. int ones, tens, hundreds, thousands; for (thousands=1; thousands<10; thousands++) { /**/ for (hundreds=0; hundreds<10; hundreds++) { /**/ /**/ for (tens=0; tens<10; tens++) { /**/ /**/ /**/ for (ones=0; ones<10; ones++) { /**/ /**/ /**/ /**/ if (ones != 2 * tens) break; /**/ /**/ /**/ /**/ if (hundreds != ones - 5) break; /**/ /**/ /**/ /**/ if (thousands != tens + hundreds) break; /**/ /**/ /**/ /**/ printf ("dd\n", thousands, hundreds, tens, ones); /**/ /**/ /**/ } /**/ /**/ } /**/ } }
100 = (9x10) + (10x1) = 90 + 10
The general function is:1. y = a*x+bb is irrelevant and we can be removed2. y = a*xlets split x into ones and tens3. x = tens*10 + ones /e.g. 23 = 2*10 + 34. p1 = Multiplier of the onesp2 = Multiplier of the tens5. y = tens*10*p2 + ones*p1 /according to the question6. x*a = tens*10*p2 + ones*p1 /according to 2.7. (tens*10 + ones)*a = tens*10*p2 + ones*p1 /according to 3.8. tens*10*a + ones*a = tens*10*p2 + ones*p1 /regroup9. tens*10*a - tens*10*p2 + ones*a - ones*p1 = 0 /regroup10. tens*10*(a-p2) + ones*(a-p1) = 0 /regroup11. assuming "tens" and "ones" are not 0 then (a-p2) and (a-p1) must be 012. a-p2 = 0a-p1 = 013. a = p2a = p114. a = p1 = p2the answer is: when the Multipliers of ones and tens are equal then the product is called a.
Well, isn't that a happy little question! If we have 80 ones, we can group them into sets of ten. So, there are 8 groups of ten in 80 ones. Just imagine those tens dancing together on your canvas, creating a beautiful harmony of numbers.
What number has 9 tens and 4 fewer ones than tens
There is no four digit number where the ones is twice the tens, the hundreds is five less than the ones, and the thousands is the sum of the tens and hundreds. int ones, tens, hundreds, thousands; for (thousands=1; thousands<10; thousands++) { /**/ for (hundreds=0; hundreds<10; hundreds++) { /**/ /**/ for (tens=0; tens<10; tens++) { /**/ /**/ /**/ for (ones=0; ones<10; ones++) { /**/ /**/ /**/ /**/ if (ones != 2 * tens) break; /**/ /**/ /**/ /**/ if (hundreds != ones - 5) break; /**/ /**/ /**/ /**/ if (thousands != tens + hundreds) break; /**/ /**/ /**/ /**/ printf ("dd\n", thousands, hundreds, tens, ones); /**/ /**/ /**/ } /**/ /**/ } /**/ } }
16
The number that has 3 tens and 2 ones is 32. In the base-10 number system, each place value represents a power of 10, so the digit in the tens place is multiplied by 10 and the digit in the ones place remains as it is. Therefore, 3 tens is equal to 30 and 2 ones is equal to 2, making the number 32.
One hundred.
Well, isn't that a happy little question! If we have 80 ones, we can group them into sets of ten. So, there are 8 groups of ten in 80 ones. Just imagine those tens dancing together on your canvas, creating a beautiful harmony of numbers.
Well, isn't that a happy little math problem! If we have 6 tens, that's like having 60, and adding 8 ones gives us a total of 68. So the number you're looking for is 68. Just like painting, sometimes all it takes is a few simple strokes to create something beautiful.
Nine tens = 90 Ten ones = 10 90 + 10 = 100
In mathematics, the number of tens in a given quantity is determined by dividing the quantity by 10. In this case, if we have 30 ones, we can divide 30 by 10 to find out how many tens are in 30 ones. The result of 30 divided by 10 is 3, so there are 3 tens in 30 ones.
100 = (9x10) + (10x1) = 90 + 10
No, 100 is not the same as 10 ones or 10 tens. In the decimal system, 100 is equivalent to 10 tens. This is because each place value in a number represents a power of 10. So, in the number 100, the digit '1' is in the hundreds place, indicating 1 hundred which is equivalent to 10 tens.
The general function is:1. y = a*x+bb is irrelevant and we can be removed2. y = a*xlets split x into ones and tens3. x = tens*10 + ones /e.g. 23 = 2*10 + 34. p1 = Multiplier of the onesp2 = Multiplier of the tens5. y = tens*10*p2 + ones*p1 /according to the question6. x*a = tens*10*p2 + ones*p1 /according to 2.7. (tens*10 + ones)*a = tens*10*p2 + ones*p1 /according to 3.8. tens*10*a + ones*a = tens*10*p2 + ones*p1 /regroup9. tens*10*a - tens*10*p2 + ones*a - ones*p1 = 0 /regroup10. tens*10*(a-p2) + ones*(a-p1) = 0 /regroup11. assuming "tens" and "ones" are not 0 then (a-p2) and (a-p1) must be 012. a-p2 = 0a-p1 = 013. a = p2a = p114. a = p1 = p2the answer is: when the Multipliers of ones and tens are equal then the product is called a.
9 tens + 12 ones = 9 × 10 + 12 × 1 = 90 + 12 = 102.