If you want your answer to be a whole number, it is divisible by 2 and 5.
180 is divisible by 2, 3, 4, 5, 9, and 10.
7 is not divisible by any of them.
Your question is impossible to answer. Any number that is divisible by both 2 and 5 will also be divisible by 10. 30 and 60 are not divisible by 9.
90
To find a number less than 100 that is divisible by 2, 5, and 9, we need to find the least common multiple (LCM) of these three numbers. The LCM of 2, 5, and 9 is 90. Therefore, the number less than 100 that is divisible by 2, 5, and 9 is 90.
If you want your answer to be a whole number, it is divisible by 2 and 5.
There are no numbers that satisfy this. If a number is divisible by both 2 and 5, then it must also be divisible by 10.
No. 189 is only evenly divisible by 3 and 9 (from the set provided). Using the following rules of divisibility on the number 189: Divisible by 2? No - the number is not even Divisible by 3? Yes - the sum of the digits (1 + 8 + 9 = 18) is divisible by 3 Divisible by 4? No - the last two digits are not evenly divisible by 4 Divisible by 5? No - the last digit is not a 0 or a 5 Divisible by 6? No - the number is not even Divisible by 9? Yes - the sum of the digits is divisible by 9 Divisible by 10? No - the number is not divisible by 2 or 5
To determine if a number is divisible by another number, you need to check if the first number can be divided by the second number without leaving a remainder. For 501105: Divisibility by 2: A number is divisible by 2 if its last digit is even. The last digit of 501105 is 5, which is odd, so 501105 is not divisible by 2. Divisibility by 3: A number is divisible by 3 if the sum of its digits is divisible by 3. The sum of the digits of 501105 is 5+0+1+1+0+5=12, which is divisible by 3, so 501105 is divisible by 3. Divisibility by 5: A number is divisible by 5 if its last digit is 0 or 5. The last digit of 501105 is 5, so 501105 is divisible by 5. Divisibility by 9: A number is divisible by 9 if the sum of its digits is divisible by 9. The sum of the digits of 501105 is 12, which is not divisible by 9, so 501105 is not divisible by 9. Divisibility by 10: A number is divisible by 10 if its last digit is 0. The last digit of 501105 is 5, so 501105 is not divisible by 10.
180 is divisible by 2, 3, 4, 5, 9, and 10.
7 is not divisible by any of them.
Your question is impossible to answer. Any number that is divisible by both 2 and 5 will also be divisible by 10. 30 and 60 are not divisible by 9.
90
The least number divisible by 2, 3, 4, 5, 6, 9, and 10 is 180.
The number is divisible by 5 then its end is either 0 or 5 The number is divisible by 9 then the sum of its digits is divisible by 9 If the number is divisible by 5 but not by 10 then it means that the number is divisible by 5 but not by 2, thus it's not an even number. The number is not even so it ends with 5 So the number is written a5a5 or aa55 or 5aa5. a+5+a+5 = 2 x a+10 which must be divisible by 9 if a = 1 then is doesn't work if a = 2 then is doesn't work if a = 3 then is doesn't work if a = 4 then 4545 or 4455 or 5445 are ok if a = 5 then is doesn't work if a = 6 then is doesn't work if a = 7 then is doesn't work if a = 8 then is doesn't work if a = 9 then is doesn't work
To be divisible by 2 the number must be even, that is its last digit must be 2, 4, 6, 8, or 0; the last digit of 26 is 6 which is one of {2, 4, 6, 8, 0} so 26 is even and divisible by 2. To be divisible by 3 sum the digits of the number; if this sum is divisible by 3 then the original number is divisible by 3. The test can be repeated on the sum until a single digit remains, in which case if this single digit is 3, 6, or 9 then the original number is divisible by 3; For 26: 2 + 6 = 8 which is not one of {3, 6, 9} so 26 is not divisible by 3. To be divisible by 5 the last digit must be a 0 or 5; the last digit of 26 is a 6 which is not 0 nor 5, so 26 is not divisible by 5. To be divisible by 9 sum the digits of the number; if this sum is divisible by 9 then the original number is divisible by 9. The test can be repeated on the sum until a single digit remains, in which case if this single digit is 9 then the original number is divisible by 9; For 26: 2 + 6 = 8 which is not 9 so 26 is not divisible by 9. 26 is divisible by 2 but not divisible by 3, 5 nor 9.