To determine if an ordered pair is a solution to an inequality, you need to substitute the values of the ordered pair into the inequality and check if the statement holds true. If the left side of the inequality evaluates to a value that satisfies the inequality when compared to the right side, then the ordered pair is a solution. If not, it is not a solution. Please provide the specific ordered pair and the inequality for a definitive answer.
To determine which ordered pair is not a solution of the inequality (3x - 2y < 12), you would need to substitute the x and y values from each ordered pair into the inequality. If the resulting expression does not satisfy the inequality, then that pair is not a solution. Please provide the ordered pairs you want me to evaluate.
To determine an ordered pair that could be a solution to an inequality, you need to substitute the values of the ordered pair into the inequality and check if it satisfies the condition. For example, if the inequality is (y < 2x + 3) and the ordered pair is (1, 4), you would substitute (x = 1) and (y = 4) to see if (4 < 2(1) + 3) holds true. If it does, then (1, 4) is a solution; if not, you would need to try another pair.
It could be but more details are required.
To determine which ordered pair could be a solution to the inequality (4y - 3x - 2 > 0), you can substitute the values of the ordered pair into the inequality. For example, if we take the ordered pair (1, 2), substituting gives (4(2) - 3(1) - 2 = 8 - 3 - 2 = 3), which is greater than 0, thus (1, 2) is a solution. You can test other pairs similarly to find more solutions.
To determine which ordered pair is not a solution of the inequality (3x - 2y < 12), you would need to substitute the x and y values from each ordered pair into the inequality. If the resulting expression does not satisfy the inequality, then that pair is not a solution. Please provide the ordered pairs you want me to evaluate.
To determine an ordered pair that could be a solution to an inequality, you need to substitute the values of the ordered pair into the inequality and check if it satisfies the condition. For example, if the inequality is (y < 2x + 3) and the ordered pair is (1, 4), you would substitute (x = 1) and (y = 4) to see if (4 < 2(1) + 3) holds true. If it does, then (1, 4) is a solution; if not, you would need to try another pair.
It could be but more details are required.
To determine which ordered pair could be a solution to the inequality (4y - 3x - 2 > 0), you can substitute the values of the ordered pair into the inequality. For example, if we take the ordered pair (1, 2), substituting gives (4(2) - 3(1) - 2 = 8 - 3 - 2 = 3), which is greater than 0, thus (1, 2) is a solution. You can test other pairs similarly to find more solutions.
To determine if an ordered pair ((x, y)) is a solution to the inequality (3y - 1 - 2x \geq 0), we can rearrange it to (3y \geq 2x + 1). For example, if we take the ordered pair ((1, 1)), we substitute (x = 1) and (y = 1): (3(1) \geq 2(1) + 1), which simplifies to (3 \geq 3). Since this is true, ((1, 1)) is a valid solution to the inequality.
Given the ordered pair (3, y), what value of ywould make the ordered pair a solution of the equation 4x − 2y = 24?12
The question does not contain an equation nor an inequality. There cannot be any ordered pair which can satisfy an expression.
Substitute the values of the ordered pair into the relation. If the equation is valid then the ordered pair is a solution, and if not then it is not.
The solution of a linear inequality in two variables like Ax + By > C is an ordered pair (x, y) that produces a true statement when the values of x and y are substituted into the inequality.
No, this is not necessarily the case. A function can have an infinite range of solutions but not an infinite domain. This means that not every ordered pair would be a solution.
Always. Every ordered pair is the solution to infinitely many equations.
That would be the "solution" to the set of equations.