IMPORTANT QUESTIONS IN SOCIAL STUDIES. Q1.WRITE THE DIFFERENCES BETWEEN GENERAL ELECTIONS AND BYE ELECTIONS? Q2.WHAT IS ECONOMIC PLANING? CHEMISTRY. Q1.DIFFERENCE BETWEEN DIAMOND AND GRAPHITE?
There is no formal definition of a outlier: it is a data point that is way out of line wit the remaining data set.If Q1 and Q3 are the lower and upper quartiles of the data set, then (Q3 - Q1) is the inter quartile range IQR. A high end outlier is determined by a value which is larger thanQ3 + k*IQR for some positive value k. k = 1.5 is sometimes used.
here first we looking on the given diagram and after this we select all the incoming input like in q1 all the input are q1=q2 0+ q1 1 or q2=q3 1 + q2 0 q1 is a state and when q2 sent 0 then its going to q1 so the value add into the q1 ok same in q2...
You need to find the median first. That will divide the data into two halves. The median is also known as Q2 or second quartile. Now take the first half of you data and find the median of that half. This is known as Q1. Do the same with the second half and that is Q3. You box has Q1 on the left, Q3 on the right and Q2 in the middle. The whiskers will be the range of your data, that is to say the upper and lower extremes. You will graph the quartiles and the extremes with the scale underneath them. A link with pictures is provided. The 5 numbers, Q1, Q2, Q3 and the extremes(max and min values) are known as the 5 number summary.
procedure: step 1: arrange your raw data in increasing order. step 2: find the Q1 is the size of the (n+1)/4th value. step 3: find the Q3 is the size of the 3(n+1)/4th value. Quartile Deviation(QD)= (Q3-Q1)/2 for example: 87 ,64,74,13,19,27,60,51,53,29,47 is the given data step 1: 13,19,27,29,47,51,53,60,64,74,87 step 2: (n+1)/4=3 therefore Q1=27 step 3: 3(n+1)/4=9 therefore Q3=6 implies QD=18.5
(q3-q1)/2
Yes. An example: the data set {1, 1, 2, 2, 2, 2, 2, 2, 2, 3, 5} has median = Q1 = Q3 = 2.
it is difference between the q1 and q3.
In order to find Q1, you must first find Q2. Q2 is the median, or middle, for the entire set of given data. If the data set is 1, 2, 2, 3, 3, 4, 4 ,4, 5, 5, 6, 7, 7, then Q2 would be 4. Therefore, the first half of the data set is 1, 2, 2, 3, 3, 4. Q1 is the median for the first half of data. Since there are an even number of entries for the first half, the two middle numbers are averaged. Thus, 2+3=5, and 5/2=2.5. Q1 equals 2.5.
To find the inner quartiles (Q1 and Q3), first arrange your data in ascending order. Q1 is the median of the lower half of the data, and Q3 is the median of the upper half. The inner quartiles divide the data into four equal parts. The outer quartiles also known as the minimum and maximum values, are the smallest and largest values in the data set.
You can calculate the distance between two charges using Coulomb's law by rearranging the formula: F = k * (q1 * q2) / r^2. Solving for distance (r) gives you: r = sqrt(k * (q1 * q2) / F) where k is the Coulomb constant, q1 and q2 are the charges, and F is the force between the charges.
Q1 is a building found at Gold Coast in Australia.
by text and numbers
by text and date
IMPORTANT QUESTIONS IN SOCIAL STUDIES. Q1.WRITE THE DIFFERENCES BETWEEN GENERAL ELECTIONS AND BYE ELECTIONS? Q2.WHAT IS ECONOMIC PLANING? CHEMISTRY. Q1.DIFFERENCE BETWEEN DIAMOND AND GRAPHITE?
The first quartile is the value such that a quarter of the data are smaller than that value and three quarters are larger. Since there are 8 observations, the quartile will be between the second and the third smallest values. Therefore, Q1 = (7+15)/2 = 11
//Library File#include//Class to hold a person's dataclass person{public:int arr_time,trans_time;};//Class to implement queueclass Queue{private:person data[5]; // An array object of the person classint front,back; // 'front' and 'back' variables to point to the front value and back valueint count; //'count' counts the no. of elements present in the queuepublic:Queue() //Constructor{front=back=0;count=0;}void inqueue(int a_tym,int t_tym) // Function to add data into the queue{if(count>=5)cout