56=2x2x2x7
56 = 7 x 8 = 7 x 23 then 56 is not a product of 3different prime numbers
The prime factorization of 56 is 2, 2, 2, and 7, so there there are two prime numbers, 2 and 7, that can evenly go into 56.
As a product of its prime factors: 2*2*2*7 = 56
There are no prime numbers that, when multiplied, equal 56. The prime factors of 56 are 2, 2, and 7. However, 2 and 7 are not prime when multiplied together.
The prime numbers (factors) of 56 are: 2 and 7
The prime numbers (factors) of 56 are: 2 and 7
The two prime numbers that equal 56 are 2 and 53. 2 is the only even prime number, and 53 is a prime number because it is only divisible by 1 and itself. When multiplied together, 2 x 53 equals 106, not 56. Therefore, there are no two prime numbers that equal 56.
56=2x2x2x7
Numbers cannot "make" another number prime. If you are looking for the prime factorization of 56, it is 23 * 7.
Well, darling, you're out of luck on this one. Prime numbers are only divisible by 1 and themselves, so there's no way to add three of them together to get 56. You might want to brush up on your math facts before trying to stump me next time.
56 = 7 x 8 = 7 x 23 then 56 is not a product of 3different prime numbers
The prime factorization of 56 is 2, 2, 2, and 7, so there there are two prime numbers, 2 and 7, that can evenly go into 56.
56 and 84 are both composite numbers, so neither are prime and they are not relatively prime either as they share several factors.
None of those four numbers are prime numbers.
As a product of its prime factors: 2*2*2*7 = 56
Two of them.