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nswer:525mL of 75% solution and 420mL of 30% solution must be mixed to produce 945mL of a 50% acid solution


Let x = 75% acid solution

y = 30% acid solution


Equations:

x + y = 945mL ----equation (1)

0.75x + 0.3y = 0.5 * 945

0.75x + 0.3y = 472.5

multiplying by 100

75x + 30y = 4725 ----equation (2)

eliminating equations (1) and (2)

-30(x + y = 945)-30

-30x -30y = -28350

75x +30y = 4725

============

45x = 23625

x=525

substitute x=525 to equation (1)

525 + y = 945

y = 945 - 525

y = 420

thus 525mL of 75% solution and 420mL of 30% solution must be mixed to produce 945mL of a 50% acid solution


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Q: What quantity of 75 per cent acid solution must be mixed with a 30 per cent solution to produce 945 mL of a 50 per cent solution?
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