A cube with sides of s units has a total surface area of 6*s^2 square units.
The largest square that you can fit in any cube will have each corner 1/4 of the way away from a corner of the cube and will have a side length of s*3√2/4 where s is the length of the sides of the cube. For a unit cube, the side length is 1 by definition, meaning that this largest square will have a side length of 3√2/4 and that its area will be 9/8 units squared.
Somehow I messed up andused 31 instead of 35 That is why you are receiving an improvement Do a Google search for Diagonal of a cube Find this website. mathcentral.uregina.ca/QQ/database/QQ.09.04/brett1.HTML - Draw a cube You will see how to find the diagonal of a cube. You use Pythagorean Theorem Draw a cube Label each side as s Draw the diagonal of the base of the cube Diagonal of base = (s^2 + s^2 )^0.5 Let the diagonal of the base be the horizontal side of the right triangle whose hypotenuse is the diagonal of the cube. The height of the cube is the vertical side of the right triangle whose hypotenuse is the diagonal of the cube. Now determine the length of the diagonal of the cube. (diagonal of base)^2 + (height of cube)^2 = (diagonal of cube )^2 Diagonal of base = (s^2 + s^2 )^0.5….Height of cube = s Use Pythagorean Theorem (diagonal of cube )^2 = (diagonal of base)^2 + (height of cube)^2 (diagonal of base)^2 = [(s^2 + s^2 )^0.5]^2 = s^2 + s^2 height of cube)^2 = s^2 (diagonal of cube)^2 = (s^2 + s^2 + s^2) (diagonal of cube )^2 = (3 * s^2) diagonal of cube = (3 * s^2)^0.5 = 35 (3 * s^2)^0.5 = 35 Square both sides 3s^2 = 31^2 = 1225 s^2 = 408.33 s = 40833^0.5 s = 20.2 cm
It is s*√3, easily proved using Pythagoras's theorem.
If the length of an edge of a cube is s units then its volume is s*s*s or s3 cubic units.
Given side S, the diagonal is S * √2. So the difference is Diagonal - side = (S √2) - S = S (√2 - 1) so Given Difference / (2 - 1) = S That's the size of the side of the square :)
A cube with sides of s units has a total surface area of 6*s^2 square units.
Surface area of a cube = side * side * 6SA = s*s*6With the SA = 54, we get54 / 6 = s*s9 = s* ss = square root of 9 = 3Volume of a cube = s * s * s3 cubed = 2727 Cubic inches
If the length of the side is S, the area of the faces of the cube is 6*S^2. There are six faces to the cube, and each face is S*S. For example, if the side of the cube is 2 inches, the area of a face is 2*2 = 4 square inches. Six faces means the overall area is 6*4 = 24 square inches.
The largest square that you can fit in any cube will have each corner 1/4 of the way away from a corner of the cube and will have a side length of s*3√2/4 where s is the length of the sides of the cube. For a unit cube, the side length is 1 by definition, meaning that this largest square will have a side length of 3√2/4 and that its area will be 9/8 units squared.
54 square inches.
A cube has 6 squares as the faces of a cube. The area of the square is A = s² where s is the length of the side. Given that area formula, we have: A = (3 centimeters)² = 9 centimeters² So the area of each face of a cube is 9 centimeters²
The base of a cube is a square, so the area of the base of the cube is the area of that square. The area of a square is s2, where s is the length of on side. Side all edges of a cube have the same length, it doesn't matter which edge you use. Example: Find the area of the base of a cube with edges of length 7: A = 72 = 49 Example: Find the area of the base of a cube with volume 8 cubic meters. The volume of a cube is equal to s3, where s is the length of a side. 23=8, so 2 is the length of a side, and the area of the base is 22 = 4.
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The word "cube" in 60's slang was a continuation of the description of people as "squares". A square was someone who was not "hip" or who had a dislike for the counterculture or Hippies. Someone who was described as a "cube" was so totally out of touch with popular counterculture that they exceeded the "square" description. "Those girls aren't just squares, they are a bunch of stressed out cubes".
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Somehow I messed up andused 31 instead of 35 That is why you are receiving an improvement Do a Google search for Diagonal of a cube Find this website. mathcentral.uregina.ca/QQ/database/QQ.09.04/brett1.HTML - Draw a cube You will see how to find the diagonal of a cube. You use Pythagorean Theorem Draw a cube Label each side as s Draw the diagonal of the base of the cube Diagonal of base = (s^2 + s^2 )^0.5 Let the diagonal of the base be the horizontal side of the right triangle whose hypotenuse is the diagonal of the cube. The height of the cube is the vertical side of the right triangle whose hypotenuse is the diagonal of the cube. Now determine the length of the diagonal of the cube. (diagonal of base)^2 + (height of cube)^2 = (diagonal of cube )^2 Diagonal of base = (s^2 + s^2 )^0.5….Height of cube = s Use Pythagorean Theorem (diagonal of cube )^2 = (diagonal of base)^2 + (height of cube)^2 (diagonal of base)^2 = [(s^2 + s^2 )^0.5]^2 = s^2 + s^2 height of cube)^2 = s^2 (diagonal of cube)^2 = (s^2 + s^2 + s^2) (diagonal of cube )^2 = (3 * s^2) diagonal of cube = (3 * s^2)^0.5 = 35 (3 * s^2)^0.5 = 35 Square both sides 3s^2 = 31^2 = 1225 s^2 = 408.33 s = 40833^0.5 s = 20.2 cm