The sum of the first n cubed numbers is the square of the nth triangular number.
171700
The absolute value of the sum of two complex numbers is less than or equal to the sum of their absolute values.
One relationship is that the sum of the nth and the previous triangular numbers is equal to the nth square number.That isT(n-1) + T(n) = S(n)where T(n) is the nth triangular number and S(n) is the nth square number.
1+3+6+10 =20
the answer is of course 12
The sum of the first n cubed numbers is the square of the nth triangular number.
It is 46.
They don't necesarily,3 is a triangular number and 10 is a triangular number. Their sum is 13 which is not a square number.They don't necesarily,3 is a triangular number and 10 is a triangular number. Their sum is 13 which is not a square number.They don't necesarily,3 is a triangular number and 10 is a triangular number. Their sum is 13 which is not a square number.They don't necesarily,3 is a triangular number and 10 is a triangular number. Their sum is 13 which is not a square number.
171700
There are an many triangular numbers that are also square numbers. Simply put, the sum of two consecutive triangular number equals a square number. Examples include 1 and 36.
The absolute value of the sum of two complex numbers is less than or equal to the sum of their absolute values.
NO! abs(2-2)=0 NOT equal to abs(2)+abs(-2)=4 - The above is technically correct, though the more thorough answer is as follows; no because the absolute value of the sum is LESS THEN OR EQUAL TO the sum of the absolute values. The simple proof the the fact that |A+B|<=|A|+|B| is called the triangular inequality. When A and B (or for that matter an infinite number of them) are both positive (or all) or both negative (or all) then they inequality is actually equal, if however any of the numbers have different signs then any other number, the inequality is less then.
One relationship is that the sum of the nth and the previous triangular numbers is equal to the nth square number.That isT(n-1) + T(n) = S(n)where T(n) is the nth triangular number and S(n) is the nth square number.
I assume you are asking the question "what two prime numbers sum to 44". There may be other pairs of prime numbers that sum to 44, but 37 and 7 are both primes and their sum = 44.
The answer would be 15 and 21. The triangular numbers are 1,3,6,10,15,21,28,36,45,55,66,78. 15 plus 21 is 36 which is on the list. 21 minus 15 is 6 and that is on the list as well.
1+3+6+10 =20