There are infinitely many pairs. One such is 1 and 98.
97, 98
The product of two numbers is the answer to multiplying the two numbers together.
97 and 98
98 = 2 x 7 x 7
To find two consecutive numbers with a product of 9506, we can set the numbers as ( n ) and ( n + 1 ). The equation becomes ( n(n + 1) = 9506 ). Solving for ( n ), we can approximate ( n^2 \approx 9506 ), leading to ( n \approx 97.5 ). The consecutive integers are 97 and 98, as ( 97 \times 98 = 9506 ).
97, 98
49 and 8
97 x 98 = 9506
8 + 10 = 188 x 10 = 80Therefore, the two numbers are 8 and ten
98 = 2 * 7 * 7
The numbers are 98 and 64
98 = 2*7^2.
The product of two numbers is the answer to multiplying the two numbers together.
97 and 98
98 = 2 x 7 x 7
To find two consecutive numbers with a product of 9506, we can set the numbers as ( n ) and ( n + 1 ). The equation becomes ( n(n + 1) = 9506 ). Solving for ( n ), we can approximate ( n^2 \approx 9506 ), leading to ( n \approx 97.5 ). The consecutive integers are 97 and 98, as ( 97 \times 98 = 9506 ).
As for example 98 as a product of its prime factors is: 2*7*7 = 98