66 X 2=132
They are: 11 times 12 = 132
132 = 11 x 12 ie 11 x 3 x 2 x 2 . the answer is there are no two prime numbers whose product is 132.
1+131=132
How about: 127+5 = 132
66 X 2=132
They are: 11 times 12 = 132
132 = 11 x 12 ie 11 x 3 x 2 x 2 . the answer is there are no two prime numbers whose product is 132.
1+131=132
How about: 127+5 = 132
113 + 19 = 132 109 + 23 = 132 103 + 29 = 132 101 + 31 = 132 89 + 43 = 132 79 + 53 = 132 73 + 59 = 132 71 + 61 = 132 So there are 8 pairs of prime numbers that sum to 132.
11 & 12 are the integers whose product is 132.
11 x 12 = 132 12 x 11 = 132 2 x 66 = 132 66 x 2 = 132
It is not possible in our Universe that two consecutive numbers can total an even number, since any two consecutive numbers must be an odd and an even (or vice versa). There are two consecutive odd numbers which total 132 ie 65 and 67
You need at least two numbers to find an LCM.
as 132 is an even number at least one of the two numbers must also be even 12 + 11 = 23 12 x 11 = 132
it would be 321 312 231 213 123 132