Depends on what operation you perform on the two numbers. And, for each operation there are infinitely many possible answers.
For example:
addition has 0 and 132, 1 and 131, etc
multiplication has 1 and 132, 0.1 and 1320, 0.001 and 13200 etc
66 X 2=132
They are: 11 times 12 = 132
132 = 11 x 12 ie 11 x 3 x 2 x 2 . the answer is there are no two prime numbers whose product is 132.
1+131=132
How about: 127+5 = 132
66 X 2=132
They are: 11 times 12 = 132
132 = 11 x 12 ie 11 x 3 x 2 x 2 . the answer is there are no two prime numbers whose product is 132.
1+131=132
How about: 127+5 = 132
113 + 19 = 132 109 + 23 = 132 103 + 29 = 132 101 + 31 = 132 89 + 43 = 132 79 + 53 = 132 73 + 59 = 132 71 + 61 = 132 So there are 8 pairs of prime numbers that sum to 132.
11 & 12 are the integers whose product is 132.
11 x 12 = 132 12 x 11 = 132 2 x 66 = 132 66 x 2 = 132
It is not possible in our Universe that two consecutive numbers can total an even number, since any two consecutive numbers must be an odd and an even (or vice versa). There are two consecutive odd numbers which total 132 ie 65 and 67
To find two numbers that multiply to -132 and add to 2, we can set them as ( x ) and ( y ). The numbers that satisfy these conditions are 12 and -11, since ( 12 \times -11 = -132 ) and ( 12 + (-11) = 1 ). Therefore, the two numbers are 12 and -11.
You need at least two numbers to find an LCM.
as 132 is an even number at least one of the two numbers must also be even 12 + 11 = 23 12 x 11 = 132