Wiki User
∙ 12y agoYou can't tell the area from that much information. In order to find the area you can measure the base and height and multiply them by each other. Then divide the product by two.
Wiki User
∙ 12y ago7X6/2
The area of a right angled triangle would be .5 * length *width where the length is the height of the triangle. To find the height of the triangle, take the sine of 45 degrees, which is the degree of the angles other than the 90 degrees, and multiply it by the length of one of the two equal sides. The width of the triangle is the length of the bottom side.
The area of ANY triangle is base x height. The height must be measured perpendicular to the base. In the case of an isosceles triangle, if you know only the length of the sides, you can figure out the height by Pythagoras' Theorem.
It depends on what information you have: one side and an angle, two different sides.
As it's an isosceles right triangle, the right angle is the angle between the two sides of equal length. Using Pythagoras, the lengths of these sides, and hence the area can be found: 2 x side2 = (6√2)2 ⇒ side2 = 62 ⇒ side = 6 ⇒ area = 1/2 x 6 x 6 = 18 sq units.
7X6/2
What is the length of a leg of an isosceles right triangle if it is area is 72 square inches?
V= area of the triangle x length
14.5 cm.
The area of a right angled triangle would be .5 * length *width where the length is the height of the triangle. To find the height of the triangle, take the sine of 45 degrees, which is the degree of the angles other than the 90 degrees, and multiply it by the length of one of the two equal sides. The width of the triangle is the length of the bottom side.
The area of ANY triangle is base x height. The height must be measured perpendicular to the base. In the case of an isosceles triangle, if you know only the length of the sides, you can figure out the height by Pythagoras' Theorem.
The length of the hypotenuse, alone, is not sufficient to determine the area of a triangle.
assuming its an isosceles triangle, then its 16 cm high
Use Pythagoras to find the perpendicular height of the triangle: 132-52 = 144 and the square root of this is the height of the triangle which is 12 cm Area = 1/2*12*10 = 60 square cm
Yes providing that it's an equilateral triangle or a right angle isosceles triangle.
As it's an isosceles right triangle, the right angle is the angle between the two sides of equal length. Using Pythagoras, the lengths of these sides, and hence the area can be found: 2 x side2 = (6√2)2 ⇒ side2 = 62 ⇒ side = 6 ⇒ area = 1/2 x 6 x 6 = 18 sq units.
It depends on what information you have: one side and an angle, two different sides.