Using 32 ft/sec2 as the acceleration due to gravity, it would be 0.0303.. miles per sec.
An object in free fall accelerates due to gravity at approximately 9.81 meters per second squared. After two seconds, its velocity can be calculated using the formula ( v = g \cdot t ), where ( g ) is the acceleration due to gravity. Thus, after two seconds, the object would be falling at about ( 19.62 ) meters per second (m/s) downward.
A falling object accelerates at a rate of 9.8 m/s2. That means that for every second that it is falling, its velocity increases by 9.8 m/s. The higher that the object is falling from, the longer it will have to speed up, thus the higher its velocity upon impact will be. (This is assuming that it does not reach terminal velocity, the velocity at which an object can no longer accelerate because it is travelling so fast that the drag force (air resistance) is equal to the force of gravity.)
Acceleration of gravity near the surface of the earth is 9.8 meters (32.2 feet) per second2. Downward velocity after 2 seconds = 19.2 meters (64.4 feet) per second.
the answer is 24-9 m/sec. yuor welcome
A freely falling Ball has the acceleration of 9.8 m/s/s so after 5 seconds its velocity will be: t=5s a=9.8m/s/s v=5s * 9.8m/s/s =49 m/s
The velocity of a freely falling object 5 seconds after being dropped is approximately 49 meters per second (m/s) downwards. This is the velocity an object reaches due to the acceleration of gravity (9.8 m/s^2) acting on it.
The speed (magnitude of velocity) is always 9.8 meters per second (32.2 feet per second) greater than it was exactly one second earlier. If the object spent "N" seconds falling, then its speed (magnitude of velocity) is 9.8N meters per second (32.2N feet per second) greater at the bottom than it was at the top. The direction of velocity remains constant under the influence of gravity ... straight down.
The rule for calculating the velocity of a falling object is V = gt, where V is the velocity, g is the acceleration due to gravity (32 ft/s^2), and t is the time in seconds. Plugging in the values: V = (32 ft/s^2) x 5 seconds = 160 ft/s. Therefore, the piano dropped 5 seconds ago is falling at a rate of 160 feet per second.
128
The rule for calculating the velocity of a falling object is V = gt, where V is velocity, g is the acceleration due to gravity (32 ft/s^2), and t is time. For an object dropped 3 seconds ago, the velocity would be V = 32 ft/s^2 * 3 s = 96 ft/s.
The velocity of a free falling object after 10 seconds is 100 m/s. This is because the acceleration due to gravity is a constant 10 m/s^2, so after 10 seconds the velocity will be 10 m/s^2 * 10 s = 100 m/s.
The speed of an object in free fall after falling for 2 seconds is approximately 19.6 m/s.
The gain velocity per second for a freely falling object is approximately 9.81 meters per second squared, which is the acceleration due to gravity on Earth. This means that the object's velocity increases by 9.81 meters per second for every second it falls.
Any change in the velocity of anything is known as 'acceleration'. In the case of a falling object near the Earth's surface, the direction of the velocity is constant, and its magnitude increases by 9.8 meters (32.2 feet) per second, every second.
The final speed of an object in free fall is known as terminal velocity. Terminal velocity on Earth can range from 54 meters per second (in SI units) to 90 meters per second based on aerodynamics.
A falling object accelerates at a rate of 9.8 m/s2. That means that for every second that it is falling, its velocity increases by 9.8 m/s. The higher that the object is falling from, the longer it will have to speed up, thus the higher its velocity upon impact will be. (This is assuming that it does not reach terminal velocity, the velocity at which an object can no longer accelerate because it is travelling so fast that the drag force (air resistance) is equal to the force of gravity.)
32 feet / second / second. Calculating the velocity of an object falling due to gravity is a complicated process because gravity decreases the further above the Earth you go. There is also a terminal velocity because of the viscosity of the air. Simply though, acceleration due to gravity at the Earth's surface is roughly 9.8m/s2. This means, after 1 second, an object will have achieved a velocity of 9.8m/s. The equation then if the viscosity of air and height above the Earth's surface are ignored is V = 9.8 x S Where V is the velocity and S is the number of seconds it has been falling.