answersLogoWhite

0


Best Answer

Using 32 ft/sec2 as the acceleration due to gravity, it would be 0.0303.. miles per sec.

User Avatar

Wiki User

12y ago
This answer is:
User Avatar

Add your answer:

Earn +20 pts
Q: What velocity in miles per second does a falling object reach after 5 seconds?
Write your answer...
Submit
Still have questions?
magnify glass
imp
Related questions

What is the velocity of freely falling objects 5 seconds after being dropped?

The velocity of a freely falling object 5 seconds after being dropped is approximately 49 meters per second (m/s) downwards. This is the velocity an object reaches due to the acceleration of gravity (9.8 m/s^2) acting on it.


How do you calculate the change in velocity of a falling object?

The change in velocity of a falling object is calculated by subtracting the initial velocity from the final velocity. The acceleration due to gravity is typically involved in this calculation. The formula for calculating the change in velocity is: change in velocity = final velocity - initial velocity.


Below is the rule for calculating the velocity of a falling object Use this rule to calculate the rate expressed in feet per second that a piano dropped 5 seconds ago is falling?

The rule for calculating the velocity of a falling object is V = gt, where V is the velocity, g is the acceleration due to gravity (32 ft/s^2), and t is the time in seconds. Plugging in the values: V = (32 ft/s^2) x 5 seconds = 160 ft/s. Therefore, the piano dropped 5 seconds ago is falling at a rate of 160 feet per second.


Below is the rule for calculating the velocity of a falling object Use this rule to calculate the rate expressed in feet per second that a piano dropped 4 seconds ago is falling?

128


Below is the rule for calculating the velocity of a falling object Use this rule to calculate the rate expressed in feet per second that a piano dropped 3 seconds ago is falling?

The rule for calculating the velocity of a falling object is V = gt, where V is velocity, g is the acceleration due to gravity (32 ft/s^2), and t is time. For an object dropped 3 seconds ago, the velocity would be V = 32 ft/s^2 * 3 s = 96 ft/s.


What is the velocity of a free falling object after 10 seconds Assume negligible air resistance and a10 ms?

The velocity of a free falling object after 10 seconds is 100 m/s. This is because the acceleration due to gravity is a constant 10 m/s^2, so after 10 seconds the velocity will be 10 m/s^2 * 10 s = 100 m/s.


Suppose an object in free fall is dropped from a building. Its starting velocity is 0 ms. What is the speed (in ms) of the object after falling 2 seconds Give your answer as a positive decimal.?

The speed of an object in free fall after falling for 2 seconds is approximately 19.6 m/s.


What is the gain velocity per second for a freely falling object?

The gain velocity per second for a freely falling object is approximately 9.81 meters per second squared, which is the acceleration due to gravity on Earth. This means that the object's velocity increases by 9.81 meters per second for every second it falls.


What is change in the velocity of a falling object?

The change in velocity of a falling object is due to gravity, causing it to accelerate continuously towards the ground. As the object falls, its velocity increases at a constant rate of approximately 9.8 m/s^2 (on Earth) until it reaches terminal velocity or impacts the ground.


What is the final velocity of a freely falling object?

The final velocity of a freely falling object is its terminal velocity, which is constant and reached when the force of gravity is balanced by air resistance. This terminal velocity can vary depending on factors such as the object's shape, size, and weight.


What equation is used to calculate the velocity of a falling objects?

32 feet / second / second. Calculating the velocity of an object falling due to gravity is a complicated process because gravity decreases the further above the Earth you go. There is also a terminal velocity because of the viscosity of the air. Simply though, acceleration due to gravity at the Earth's surface is roughly 9.8m/s2. This means, after 1 second, an object will have achieved a velocity of 9.8m/s. The equation then if the viscosity of air and height above the Earth's surface are ignored is V = 9.8 x S Where V is the velocity and S is the number of seconds it has been falling.


How does height affect the velocity of a falling body?

A falling object accelerates at a rate of 9.8 m/s2. That means that for every second that it is falling, its velocity increases by 9.8 m/s. The higher that the object is falling from, the longer it will have to speed up, thus the higher its velocity upon impact will be. (This is assuming that it does not reach terminal velocity, the velocity at which an object can no longer accelerate because it is travelling so fast that the drag force (air resistance) is equal to the force of gravity.)