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A ball is dropped from the top of a building and hits the ground 3 seconds later. a. what is the height if the building b. with what speed did it hit the ground?

a. 144 feet b. 96 ft/sec.


What would be the change in velocity for a 10 gram object dropped from the roof of a 20 meter building if it takes 2 seconds to reach the ground Hint acceleration due to gravity is 9.8 ms²?

Acceleration = (change in velocity) / (time for the change)9.8 = (change in velocity) / (2 seconds)9.8 x 2 = change in velocity = 19.6 meters per second .Hint: The mass of the object and the height of the building are there just tothrow you off balance. You don't need either of them to answer the question.


What will be the change in velocity for a 10 gram object dropped from the roof of a 20 Meter building if it takes 2 seconds to reach the ground?

Assuming the object is in free fall, the change in velocity will be approximately 19.6 m/s downward. This is calculated using the formula v = at, where acceleration due to gravity is approximately 9.8 m/s^2 and time is 2 seconds.


A ball was dropped on a top of the building and hits the ground after 15 s. What is the height of the building?

381 metres


What would be the change in velocity for a 10 gram object dropped from the roof of a 20 meter building if it takes 2 seconds to reach the ground Hint acceleration due to gravity is 98 ms²?

In two seconds of fall, the speed increases 19.6 meters (64.4 feet) per second. The magnitude of velocity increases by that amount, while the direction of velocity doesn't change.


If an object is dropped from a tall building and hits the ground 3.0 sec later how tall is the building?

44 meters tall


What would be the change in velocity for a 10 gram object dropped from the roof of a 20-meter building if it takes 2 seconds to reach the ground?

The change in velocity can be calculated using the equation v = gt, where g is the acceleration due to gravity (9.8 m/s^2) and t is the time taken (2 seconds). So, the change in velocity would be 9.8 m/s^2 * 2 s = 19.6 m/s.


A rock is dropped from a cliff and hits the ground 6.0 seconds later How high is the cliff?

176.4 meters


What If a ball is dropped from the top of a building and it hits the ground 1.0 seconds later.how high is the building?

The height of the building can be calculated using the formula: h = (1/2)gt^2, where h is the height, g is the acceleration due to gravity (9.8 m/s^2), and t is the time taken to reach the ground (1.0 seconds in this case). Substituting the values, we get h = (1/2)(9.8)(1.0)^2 = 4.9 meters. Therefore, the height of the building is 4.9 meters.


How many seconds will it take for an egg dropped from the top of a 363 foot tall building to hit the ground?

Ignoring air resistance . . .H = 1/2 G t2t = sqrt(2H/G) = sqrt(2 x 363 / 32.2) = 4.75 seconds (rounded)


What is the height of a tower if a rock dropped from it hits the ground after falling for 2 seconds?

19.6 meters / 64.4 ft


How far in to the ground would a quarter go if you dropped it off the Empire State Building?

6 feet