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When 3n divided by 7 the remainder is 4 What is the remainder when 2n is divided by 7?
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-3n plus 5n plus 4 equals -4 solve for n?
-3n+5n+4 = -4 2n = -4-4 2n = -8 n = -4
What is 3n plus 3 equals n plus 7?
3n+3=n+7 3n+3-n=n+7-n (subtract n from both sides) 2n+3=7 2n+3-3=7-3 (subtract 3 from both sides ) 2n=4 2n/2=4/2 (divided by 2 on both the sides) n=2 Answer: n=2
How do you solve n in factorial (3xn plus 9) divided by factorial (2xn plus 4)144?
You cannot, because there is no solution.5 is not a factor of 144. Therefore 5 is not a factor of (3n + 9)! / (2n + 4)!Therefore (3n + 9) - (2n + 4) < 5n < 0.Also, 2n + 4 must be non-negative.ie 2n >= -4 or n >= -2.So the only possible values for n are -1 and -2.But n = -1 gives 6!/2! = 720/2 = 360while n = -2 gives 3!/0! = 6
How do i Solve for n 2n-3n equals one third n plus 14?
The question seems ambigous, but I will consider n 2n to be solving for n:2n - 3n = n/3 + 14-n = n/3 + 14-3n = n + 42-4n = 42Thus, the solution is n = -42/4 = -21/2 = -10.5.
N plus 4 plus 2n plus 5?
3n + 9 = 3(n + 3)
Why do prime numbers have a remainder of 1 or 5 when divided by 6?
If the number has a remainder of 2 or 4 when divided by 6, it is an even number, so it is not prime number. 6n + 2 = 2 (3n + 1), so it is divisible by 2. 6n + 4 = 2 (3n + 2), so it is divisible by 2. If the number has a remainder of 3 when divided by 6, it is divisible by 3, so it is not a prime number. 6n + 3 = 3 (2n + 1), so it is divisible by 3. However, there are two prime numbers that do not have a remainder of 1 or 5 when divided by 6 : 2 and 3
-3n plus 5n plus 4 equals -4 solve for n?
-3n+5n+4 = -4 2n = -4-4 2n = -8 n = -4
What is 3n plus 3 equals n plus 7?
3n+3=n+7 3n+3-n=n+7-n (subtract n from both sides) 2n+3=7 2n+3-3=7-3 (subtract 3 from both sides ) 2n=4 2n/2=4/2 (divided by 2 on both the sides) n=2 Answer: n=2
What is 2n-4 7n plus 7?
5n + 7 = 28 + 2n (-2n) 3n + 7 = 28 (-7) 3n = 21 therefore, n = 7
Divide m2n3 over p3 by mp over n2 equals?
The expression m^2n^3/p^3 divided by mp/n^2 can be simplified as (m^2n^3/p^3) / (mp/n^2). This simplifies to (m^3n^5)/(p^3n) = m^3n^4/p^3.
What is 3n to the fourth power over 3n to the third power?
3n^4 divided by 3n^3 = n
What is 2n 4 plus 3n a monomial a binomial or a polynomial?
It is a binomial, which is also a polynomial.
How do you solve n in factorial (3xn plus 9) divided by factorial (2xn plus 4)144?
You cannot, because there is no solution.5 is not a factor of 144. Therefore 5 is not a factor of (3n + 9)! / (2n + 4)!Therefore (3n + 9) - (2n + 4) < 5n < 0.Also, 2n + 4 must be non-negative.ie 2n >= -4 or n >= -2.So the only possible values for n are -1 and -2.But n = -1 gives 6!/2! = 720/2 = 360while n = -2 gives 3!/0! = 6
How do i Solve for n 2n-3n equals one third n plus 14?
The question seems ambigous, but I will consider n 2n to be solving for n:2n - 3n = n/3 + 14-n = n/3 + 14-3n = n + 42-4n = 42Thus, the solution is n = -42/4 = -21/2 = -10.5.
N plus 4 plus 2n plus 5?
3n + 9 = 3(n + 3)
What number as a remainder of 1 when divided by 2 as a remainder of 2 when divided by 3 as a remainder of 3 when divided by 4 and a remainder of 4 when divided by 5?
59
What is the remainder of 74 by 5?
74 divided by 5 equals 14 with a remainder of 4
