No. 3n is not a factor of 3n + 7.
No. 3n is not a factor of 3n + 7.
No. 3n isn't a factor of 3n + 7. The GCF of 3n + 7 and 9n is 1.
The GCF is 3n.
If that's +25, that factors to (3n - 5)(3n - 5) or (3n - 5)2
Yes. 3n2/12n3 = 1/4n
The first, second, third, fourth, and fifth terms of 3n - 7 are as follows:1: -42: -13: 24: 55: 8
3n+2 + (3n+3 - 3n+1) = 3n+1+1 + (3n+1+2 - 3n+1) = 3*3n+1 + (9*3n+1 - 3n+1)= (3+9-1)*3n+1 = 11*3n+1.
(9n2 - 121) = (3n + 11) (3n - 11)
1/3n
1/3n
8
(3n)(3n-1) = 3n * 3n - 3n * 1 Now, perform the multiplication: (3n * 3n) = 9n^2 (3n * 1) = 3n So, (3n)(3n-1) simplifies to: 9n^2 - 3n
3n + 2 + (3n + 3 - 3n + 1) = 3n + 2 + (3n + 3 - 3n + 1) = 3n + 2 + (4) = 3n + 6
Is it a. 3n square and 3n ans. 3n b. 3n *2 and 3n ans.3n ans. 3n for both!!
(8m - 3n)^2 I assume you mean 'squared' , when you write 'square 2'. Because means raising to the power of '2'. Whereas 'cubing' means raising to the power of '3'. To answer (8m - 3n)(8m - 3n( = 64m^2 - 24mn - 24 mn + 9n^2 = 64m^2 - 48 mn + 9n^2 Done!!!!
The expression 3n times 3n can be simplified by multiplying the coefficients (3 * 3) and adding the exponents (n + n). This results in 9n^2, where n is raised to the power of 2. This simplification follows the rules of exponentiation, specifically the rule that states when multiplying two terms with the same base, you add the exponents.