The straight line equation will then be: y = 3x+5
-- a straight line -- the slope of the line is ' 1 ' -- the line passes through the point [y= -3] on the y-axis
If: slope is 3 and point is (1, 4) Then: y = 3x+1
Point: (2, 17)Slope: 7Equation: y = 2x+13
Slope=8 point=(-7,3)
To write the point-slope equation of a line that passes through the point (5, 5), you need a slope (m) as well. The point-slope form is given by the equation ( y - y_1 = m(x - x_1) ). If the slope is not provided, you can express the equation generically as ( y - 5 = m(x - 5) ), where ( m ) is the slope of the line. If you have a specific slope, you can substitute it into the equation.
7
The line is vertical and so the slope is undefined.
For example, if the slope at a certain point is 1.5, you can draw a line that goes through the specified point, with that slope. The line would represent the slope at that point. If you want to graph the slope at ALL POINTS, take the derivative of the function, and graph the derivative. The derivative shows the slope of a function at all points.
yes you can graph it. The equation is y = mx + b where m is slope and b is y intercept. Simply plug in x,y, and m and solve for b. The y intercept is at x = 0 and y = b so you can draw the graph between this point and the given point
-- a straight line -- the slope of the line is ' 1 ' -- the line passes through the point [y= -3] on the y-axis
33
Write the equation of a line in slope-intercept form that has a slope of -2 and passes through the point (2, -8).
The slope of a line can be determined by examining the graph; only one line through a point has a particular slope.
If: slope is 3 and point is (1, 4) Then: y = 3x+1
If: slope is 3 and point is (1, 4) Then: y = 3x+1
Point: (2, 17)Slope: 7Equation: y = 2x+13
Point: (1, 4) Slope: -3 Equation: y = -3x+7