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decreases i believe(:

Q: When cell size increases the surface area to volume ratio does what?

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It increases.

To obtain the ratio of surface area to volume, divide the surface area by the volume.

As a cell becomes larger the surface area to volume ratio gets smaller. The volume increases by the square of the surface area. That is the main reason that one celled organisms are small.

A smaller cell has a higher surface area to volume ratio. A reason for this is volume is cubic (3D) and surface area is 2D so when surface area increases a little bit, the volume increases exponentially. And when the surface area shrinks a little bit, the volume decreases exponentially.

to obtain the ratio of surface area to volume, divide the surface area by the volume.

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d. surface area increases and the volume does not increase at the same rate, leading to a decrease in surface area to volume ratio.

As volume increases surface area increase, but the higher the volume the less surface area in the ratio. For example. A cube 1mmx1mmx1mm has volume of 1mm3 surface area of 6mm2 which is a ration of 1:6 and a cube of 2mmx2mmx2mm has a volume of 8mm3 and surface area of 24mm2 which is a ratio of 1:3.

The cell's ratio of surface area to volume would decrease if its volume increases more rapidly than its surface area.

As cell volume increases, the ratio of cell surface area to cell volume decreases. This is because the surface area increases by a square factor while the volume increases by a cube factor. A higher surface area to volume ratio is more favorable for efficient nutrient exchange and waste removal in cells.

As the cell size increases, the surface area to volume ratio decreases. This is because the volume of the cell increases at a faster rate than its surface area. A low surface area to volume ratio can impact the cell's ability to efficiently exchange nutrients, gases, and waste with its environment.

The ratio decreases.

The ratio decreases.

As the cell gets bigger, the surface to volume ratio gets smaller.

If the length of the cube's side is 'S', then the surface area is 6S2 and the volume is S3 .The ratio of surface area to volume is 6S2/S3 = 6/S .This number is inversely proportional to 'S'. So as the side increases ...causing the volume to increase ... the ratio does decrease, yes.

As a cell grows larger, its volume increases faster than its surface area, leading to a decrease in the surface area-to-volume ratio. This can limit the cell's ability to efficiently exchange materials with its environment, affecting its overall functioning.

As the volume of a cell increases, the surface area of the cell also increases, but at a slower rate. This can lead to a decrease in the surface area-to-volume ratio of the cell. A decreased surface area-to-volume ratio can impact the cell's ability to efficiently exchange materials with its environment, potentially affecting its overall functioning.

No, a basketball does not have a high surface-to-volume ratio because the volume of a sphere increases more rapidly than its surface area as its size increases.