It is a positive reciprocal. x-a = 1/xa or equivalently, (1/x)a
It is a positive reciprocal. x-a = 1/xa or equivalently, (1/x)a
a negative number plus a negative number is negative. here is a proof.(-x)+(-x)(-1)x+(-1)x-1(x+x)-1(2x)-2xa negative number times a negative number is positive though.
Let X = *positive number 1* Let Y = *positive number 2* X times Y
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It is a positive reciprocal. x-a = 1/xa or equivalently, (1/x)a
A positive number multiplied by a positive number will give a positive answer:1 x 1 = 1In contrast, a negative number multiplied by a positive number gives a negative answer:-1 x 1 = -1Finally two negative numbers multiplied together give a positive answer:-1 x -1 = 1
It is a positive reciprocal. x-a = 1/xa or equivalently, (1/x)a
Given any positive odd integer x the number of positive even integers less than x is given by (x-1)/2.
One 0 and 1 0 X 0 = 0 1 X 1 = 1Only positive 1 though.Negative 1 will produce the answer of a positive 1.Solve x = x^2x^2 - x = 0x ( x - 1 ) = 0Has solutions x=0 and x=1
First we can solve for y by factoring it out: y(x+1)+x=30, so y=(30-x)/(x+1)= -1+31/(x+1). Let's start by assuming x and y are positive integers and look for a logical contradiction. Since y is positive, the right side (30-x)/(x+1) must be positive. Since x (and therefore x+1) is positive, 30-x must be positive. Therefore x is less than 31. But hold on! Since y is an integer, y+1=31/(x+1) is an integer. Since 31 is only divisible by 1 and 31, y+1 is an integer implies that (x+1) is 1 or 31, making x either 0 or 30. However, x is positive and less 30, which is impossible! There it cannot be the case that x and y are both positive integers.AnswerIt's not as complicated as that. Just add 1 to both sides and factorise, and you get: (x+1)(y+1) = 31. Since 31 is prime, one of its factors must be either 1 or -1. So we'd get x+1=1 (so x=0) or else x+1=-1 (so x=-2), or else y=0 or y=-2. But the question says x and y have to be positive.
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A negative exponent becomes positive in the reciprocal. So if you have a number a^x where x is negative, then, a^x = 1/(a^-x) and, since x is negative, -x is positive.
a negative number plus a negative number is negative. here is a proof.(-x)+(-x)(-1)x+(-1)x-1(x+x)-1(2x)-2xa negative number times a negative number is positive though.
Let X = *positive number 1* Let Y = *positive number 2* X times Y
It is the inverse of x to the positive value of that power. So x-a = 1/xa or (1/x)a
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