Since I can't see either the illuminated area or the list of choices, my
chance of selecting the appropriate equation is looking rather dim.
area of the rectangle..
You use the equation Area = width x length. And solve for the width. You solve it by dividing both sides by the length to get.. Area/length = width
R = (density)(Length)/(Area) Unit of resistance is Ohms.
By forming a quadratic equation from the information given and then the length and width can be found by solving the equation.
You need the height as well to find the area, but the proper equation would be A= 5.5h
Length x Width = Area
The answer is in the question "area = length multiplied by width" the equation tells you what the surface area of something (eg a football pitch) is.
The base equation for calculating the area of a rectangle is length multiplied by width.
length * width
area of the rectangle..
You use the equation Area = width x length. And solve for the width. You solve it by dividing both sides by the length to get.. Area/length = width
R = (density)(Length)/(Area) Unit of resistance is Ohms.
By forming a quadratic equation from the information given and then the length and width can be found by solving the equation.
If you are trying to find the width of a rectangle with length and area then divide the area by the length. A=LxW. Simply divide both sides of the equation by the length and you'll have the width. W=A/L
the equations tell you what the surface area of somthing is
You need the height as well to find the area, but the proper equation would be A= 5.5h
pi*a*b where a = half length of major axis (horizontal) and b = half length of minor axis (vertical)