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What is the range of the equation y 8x2 - 10?
Without an equality sign the given terms can't be considered to be an equation
How do you identify the polynominal by name and degree of -8x2 -2x 8?
-8x2 - 2x + 8 this is a quadratic equation or a second order polynomial it is a second order polynomial because it has a term in x2 For every polynomial we name it according to the highest power term in the equation.......
What is the discriminant of this equation 8x2 5x 6 0?
To find the discriminant of the quadratic equation (8x^2 + 5x + 6 = 0), we use the formula (D = b^2 - 4ac), where (a = 8), (b = 5), and (c = 6). Substituting these values gives us (D = 5^2 - 4(8)(6) = 25 - 192 = -167). Since the discriminant is negative, this indicates that the equation has no real solutions and two complex solutions.
Solve x3 plus 7x equals 8x2?
x3 + 7x = 8x2x3 + 7x - 8x2 = 0 [subtract 8x2 from both sides]x(x2 + 7 - 8x) = 0 [factor out x]x(x-1)(x-7) = 0 [factor]Since the product of the three factors x, x-1, and x-7 equals zero, any of the three expressions could equal zero:x = 0x - 1 = 0, x = 1x - 7 = 0, x = 7Therefore, there are three solutions to the equation x3 + 7x = 8x2:x = 0x = 1x = 7Or, in set notation: x = {0,1,7}
8x2 minus 13x minus 6?
(8x2)-(13x-16)= -78
What are the factors of this quadratic equation 8x2 plus 2x -1?
8x2 + 2x - 1 = 8x2 + 4x - 2x - 1 = 4x(2x + 1) - 1(2x + 1) = (4x - 1)(2x + 1)
What is the range of the equation y 8x2 - 10?
Without an equality sign the given terms can't be considered to be an equation
Solve the equation by factoring 15 equals 8x2-14x?
15 = 8x2 - 14x; whence, 8x2 - 14x - 15 = (2x - 5)(4x + 3) = 0. Therefore, x = 5/2 or -3/4.
What is the solution set of the quadratic equation 8x2 plus 2x plus 1 0?
There is no equals sign visible but, taking the equation to be8x2 + 2x + 1 = 0,the solutions are the complex conjugate pair, -1.25 ± 0.330719*i where i is the imaginary square root of -1.
How do you identify the polynominal by name and degree of -8x2 -2x 8?
-8x2 - 2x + 8 this is a quadratic equation or a second order polynomial it is a second order polynomial because it has a term in x2 For every polynomial we name it according to the highest power term in the equation.......
What is the discriminant of this equation 8x2 5x 6 0?
To find the discriminant of the quadratic equation (8x^2 + 5x + 6 = 0), we use the formula (D = b^2 - 4ac), where (a = 8), (b = 5), and (c = 6). Substituting these values gives us (D = 5^2 - 4(8)(6) = 25 - 192 = -167). Since the discriminant is negative, this indicates that the equation has no real solutions and two complex solutions.
How many real number solutions does the equation -8x2-8x-2 equals 0 have?
Divide all terms by -2: 4x2+4x+1 = 0 (2x+1)(2x+1) = 0 x = -1/2 and also x = -1/2 The quadratic equation has 2 equal roots.
How do you get the product 16 with the numbers 2 3 5 and 8?
You can multiply 8x2 or if you can put addition into the equation you can do (3+5)x2! If you need proof here it is 8x2 can be shown as 8+8 Which equals 16.
Solve x3 plus 7x equals 8x2?
x3 + 7x = 8x2x3 + 7x - 8x2 = 0 [subtract 8x2 from both sides]x(x2 + 7 - 8x) = 0 [factor out x]x(x-1)(x-7) = 0 [factor]Since the product of the three factors x, x-1, and x-7 equals zero, any of the three expressions could equal zero:x = 0x - 1 = 0, x = 1x - 7 = 0, x = 7Therefore, there are three solutions to the equation x3 + 7x = 8x2:x = 0x = 1x = 7Or, in set notation: x = {0,1,7}
What does 8x2 equal?
8x2 is 16 or 16/2=8
What is the discriminant of this equation 8x2 plus 5x plus 6 equals 0?
It is: 25-4(8*6) = -167
8x2 minus 13x minus 6?
(8x2)-(13x-16)= -78
