The equation is -x2 - 4 = 14 or -x2 = 18 which is the same as x2 = -18. That is the quadratic equation.
You cant solve it unless it is an equation. To be an equation it must have an equals sign.
have to put it was 2x and not x2--back to the problem--2x-x-4=0x=4* * * * *True, but the question, in all likelihood WAS x2 - x - 4 = 0and the solutions to that equation are -1.561553 and 2.561553
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You don't have an equation there.
The equation is -x2 - 4 = 14 or -x2 = 18 which is the same as x2 = -18. That is the quadratic equation.
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If this is an equation you left out the equal sign. Do you mean y8=y12-4. If so add 4 to both sides. You have 4+y8=y12. Then substract y8 from both sides. You have 4=y4. Divide both sides by 4. You have y=1.
The equation of a circle centered at the origin is x2 + y2 = r2; in this case, x2 + y2 = 64.The equation of a circle centered at the origin is x2 + y2 = r2; in this case, x2 + y2 = 64.The equation of a circle centered at the origin is x2 + y2 = r2; in this case, x2 + y2 = 64.The equation of a circle centered at the origin is x2 + y2 = r2; in this case, x2 + y2 = 64.
You cant solve it unless it is an equation. To be an equation it must have an equals sign.
it is not an equation (there no equality in it!)
what number do you add in the equation x2-16x=23
The quadratic formula cannot be used to solve an equation if the coefficient of the equation's x2-term is 0.
have to put it was 2x and not x2--back to the problem--2x-x-4=0x=4* * * * *True, but the question, in all likelihood WAS x2 - x - 4 = 0and the solutions to that equation are -1.561553 and 2.561553
13
You don't have an equation there.
5. A circle with centre (0,0) has equation: x2 + y2 = radius2 With: x2 + y2 = 25 = 52 The radius is 5.