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What is the slope of a line perpendicular to the line 3x plus y equals 7?
Slope of given line = -3 Therefore, slope of perpendicular = 1/3
What is the slope of a line perpendicular to the line whose equation is y equals 2x plus 7?
It is -1/2
Given a line with a slope of 1 7 what is the slope of any line that lies perpendicular to it?
The slope of a line perpendicular to one with slope m is -1/m. So for a line with slope 1/7, any line perpendicular to it will have: slope = -1 / (1/7) = -7
What is the equation of the line that is perpendicular to -x y 7 and passes through -1 -1?
Without an equality sign and not knowing the plus or minus values of y and 7 it can't be considered to be a straight line equation therefore finding its perpendicular equation is impossible.
What is the slope of the line perpendicular to 7y equals 3x-6?
Slope of the given line is 3/7 So slope of perpendicular line is -7/3
What is the slope of a line perpendicular to the line 3x plus y equals 7?
Slope of given line = -3 Therefore, slope of perpendicular = 1/3
Find the slope of a line perpendicular to 4x plus 5y equals 7?
45
What is the slope of every line perpendicular to the graph of this equation 4x plus 5y equals 7?
4x+5y = 7 5y = -4x+7 y = -4/5x+7/5 in slope intercept form So the slope of the perpendicular line is plus 5/4
What is the slope of a line perpendicular to the line whose equation is y equals 2x plus 7?
It is -1/2
Given a line with a slope of 1 7 what is the slope of any line that lies perpendicular to it?
The slope of a line perpendicular to one with slope m is -1/m. So for a line with slope 1/7, any line perpendicular to it will have: slope = -1 / (1/7) = -7
What is the perpendicular ditance from the point 7 5 to the line 3x plus 4y -16 equals 0?
If you mean the perpendicular distance from the coordinate of (7, 5) to the straight line 3x+4y-16 = 0 then it works out as 5 units.
What is the equation of the line that is perpendicular to -x y 7 and passes through -1 -1?
Without an equality sign and not knowing the plus or minus values of y and 7 it can't be considered to be a straight line equation therefore finding its perpendicular equation is impossible.
What is the slope of the line perpendicular to 7y equals 3x-6?
Slope of the given line is 3/7 So slope of perpendicular line is -7/3
What is the perpendicular bisector equation of the line y equals x plus 5 spanning the circle x2 plus 4x plus y2 -18y plus 59 equals 0?
Equation of line: y = x+5 Equation of circle: x^2 +4x +y^2 -18y +59 = 0 The line intersects the circle at: (-1, 4) and (3, 8) Midpoint of line (1, 6) Slope of line: 1 Perpendicular slope: -1 Perpendicular bisector equation: y-6 = -1(x-1) => y = -x+7 Perpendicular bisector equation in its general form: x+y-7 = 0
Graph the line perpendicular to 7x plus 10y equals 4.5?
7x + 10y = 4.5 : 10y = -7x + 4.5 : y = -x.7/10 + 0.45, the gradient of this line is -7/10 Two straight lines are perpendicular if the product of their gradients is -1. Let the equation for the perpendicular line be y = mx + c Then m x -7/10 = -1 : m = 10/7 The equation for the perpendicular line is y = x.10/7 + c If the values of x and y for the point of intersection are provided then these can be substituted in the perpendicular line equation and the value of c obtained. If appropriate, the equation can then be restructured to a format similar to the original equation.
What is the slope of the line perpendicular to the line y equals 5x plus 7?
y = 5X + 7 is of the form y = m1x + c Here m = 5 If we want a line perpendicular to this, then its equation would be y = m2x + c, such that m1m2 = -1 We have m1 = 5. Hence m2 = -1/5
What is the length of the line from 7 5 which is perpendicular to the line of 3x plus 4y minus 16 equals 0?
Equation of (7, 5) = 4x-3y-13 = 0 Intersection of the straight line equations = (4, 1) Length of line is the square root of the sum of (7-4)2+(5-1)2 =25 Therefore: length of the line from (7, 5) perpendicular to 3x+4y-16 is 5 units
