The formula is: 0.5*(n2-3n) = diagonals whereas n is the number of sides of the polygon
14 diagonals
The five sided Polygon has 5 diagonals
A polygon with 14 diagonals will have 7 sides
The diagonals (drawn from a point) help in dividing the regular polygon into smaller triangles. The sum of the areas of these smaller triangles help in determining the total area of the polygon.
An octacontakaidigon is a polygon with 82 sides. The formula to calculate the number of diagonals in a polygon is ( \frac{n(n-3)}{2} ), where ( n ) is the number of sides. For an octacontakaidigon, this would be ( \frac{82(82-3)}{2} = \frac{82 \times 79}{2} = 3239 ). Thus, an octacontakaidigon has a total of 3,239 diagonals.
14 diagonals
It has 20 diagonals
Total diagonals formula: 0.5*(n^2 -3n) whereas n is the number of sides of the polygon
The five sided Polygon has 5 diagonals
A 7 sided polygon has 14 diagonals
It is: 0.5*(n2-3n) = diagonals whereas n is the number of sides of the polygon
Number of diagonals = 1/2*(n2-3n) where n = the number of sides of the polygon.
A polygon with 14 diagonals will have 7 sides
The diagonals (drawn from a point) help in dividing the regular polygon into smaller triangles. The sum of the areas of these smaller triangles help in determining the total area of the polygon.
The equation is: 0.5*(n2-3n) = diagonals whereas n is the number of sides of the polygon
You can find the number of diagonals in a polygon using the formula n(n-3)/2, where n is the number of sides. Therefore an 11 sided polygon has 44 diagonals.
It is: 0.5*(n2-3n) = diagonals whereas 'n' is the number of sides of the polygon