-4 is the first negative term. The progression is 24,20,16,12,8,4,0,-4,...
It is an Arithmetic Progression with a constant difference of 11 and first term 15.
In an arithmetic progression the difference between each term (except the first) and the one before is a constant. In a geometric progression, their ratio is a constant. That is, Arithmetic progression U(n) - U(n-1) = d, where d, the common difference, is a constant and n = 2, 3, 4, ... Equivalently, U(n) = U(n-1) + d = U(1) + (n-1)*d Geometric progression U(n) / U(n-1) = r, where r, the common ratio is a non-zero constant and n = 2, 3, 4, ... Equivalently, U(n) = U(n-1)*r = U(1)*r^(n-1).
To find the first term of an arithmetic progression (AP), you need at least two pieces of information: the common difference and either the second term or the sum of the first few terms. The first term can be represented as ( a ), and the ( n )-th term can be expressed as ( a_n = a + (n-1)d ), where ( d ) is the common difference. If you know the second term, you can rearrange it to find ( a = a_2 - d ). Without specific values or additional context, the first term cannot be determined.
There are 5 common differences between seventh and twelfth terms, so the CD is 2.5/5 ie 0.5. First term is therefore 15 - 6 x 0.5 = 12.
If a is the first term and r the common difference, then the nth term is tn = a * (n-1)r So t16 = a + 15r Then 6*t16 = 6(a + 15r) or 6a + 90r No further simplifiaction is possible.
For an Arithmetic Progression, Sum = 15[a + 7d].{a = first term and d = common difference} For a Geometric Progression, Sum = a[1-r^15]/(r-1).{r = common ratio }.
2
It is an Arithmetic Progression with a constant difference of 11 and first term 15.
RAMANUJANRAMANUJAN
You can use one of the formulae for the sum of an arithmetic progression to calculate that.
In an arithmetic progression the difference between each term (except the first) and the one before is a constant. In a geometric progression, their ratio is a constant. That is, Arithmetic progression U(n) - U(n-1) = d, where d, the common difference, is a constant and n = 2, 3, 4, ... Equivalently, U(n) = U(n-1) + d = U(1) + (n-1)*d Geometric progression U(n) / U(n-1) = r, where r, the common ratio is a non-zero constant and n = 2, 3, 4, ... Equivalently, U(n) = U(n-1)*r = U(1)*r^(n-1).
The formula for the sum of the first n terms of an arithmetic progression is Sn = n/2 * (a + l), where Sn is the sum, n is the number of terms, a is the first term, and l is the last term.
In an arithmetic progression the difference between each term (except the first) and the one before is a constant. In a geometric progression, their ratio is a constant.That is,Arithmetic progressionU(n) - U(n-1) = d, where d, the common difference, is a constant and n = 2, 3, 4, ...Equivalently,U(n) = U(n-1) + d = U(1) + (n-1)*dGeometric progressionU(n) / U(n-1) = r, where r, the common ratio is a non-zero constant and n = 2, 3, 4, ...Equivalently,U(n) = U(n-1)*r = U(1)*r^(n-1).
It appears to have been Svante Arrhenius (1859-1927) in 1896, a Swedish scientist who developed what is now know as the 'greenhouse gas law':"if the quantity of carbonic acid increases in geometric progression, the augmentation of the temperature will increase nearly in arithmetic progression"
35 minus 4 differences, ie 4 x 6 so first term is 11 and progression runs 11,17,23,29,35...
They are both adjectives. The first relates to geometry and the second to arithmetic.
There are 5 common differences between seventh and twelfth terms, so the CD is 2.5/5 ie 0.5. First term is therefore 15 - 6 x 0.5 = 12.