-9, -7
You could use an equation to figure this out. x is the first number and x+2 is the second number. The equation becomes (x)(x+2) = 63. x comes out to b 7, and x plus 2 is 9. Since a negative times a negative is a positive, those numbers can be changed to -7 and -9.
Two negative consecutive odd integers that have a product of 63 are -7 and -9. -7 is larger than -9. -7 is the answer.
-7
Their product is 143.
The two consecutive, odd integers whose product equals 143 are 11 and 13.
The integers are 5 and 7.
Two negative consecutive odd integers that have a product of 63 are -7 and -9. -7 is larger than -9. -7 is the answer.
The two consecutive odd integers having a product of 99 are 9 and 11.
what is the formula to use to solve the product of two consecutive odd integers
-7
Consecutive odd integers would be 5 and 7.
-13, -15 and -17
The two consecutive negative odd integers having 74 as the sum of their squares are -5 and -7.
Their product is 143.
The two consecutive, odd integers whose product equals 143 are 11 and 13.
The integers are 5 and 7.
There is no set of three consecutive odd or even integers whose sum is negative 31.
Let the two consecutive negative odd integers be ( x ) and ( x + 2 ). The equation for their product is ( x(x + 2) = 399 ). This simplifies to ( x^2 + 2x - 399 = 0 ). Solving this quadratic equation, we find that the integers are ( -19 ) and ( -17 ), since ( -19 \times -17 = 399 ).