c+3
Int = 3x^(2) dy y = 3x^(3) / 3 + c y = x^(3) + C
C-3 = 1/(c3)
c=61 - 3 =58
-2
a = 3b - c a + c = 3b - c + c a + c = 3b (a + c)/3 = 3b/3 ( a + c ) / 3 = b Do your homework.
3 digits in an area code
c+3
Nothing, c--3 is syntactical error.
−3°C > 2°C −3°C < 2°C 3°C > −2°C 3°C < −2°c one of theses
four a = 1 c = 3 a + c = 1 + 3 = 4
C-3
The expression c multiplied by c multiplied by c can be written as c^3, which is read as "c cubed." This represents c raised to the power of 3, meaning c multiplied by itself three times. So, c^3 is equal to c * c * c, which simplifies to c multiplied by c squared.
#include<stdio.h> #include<conio.h> void main() { int a[3][3],b[3][3],c[3][3],r,c; for(r=0;r<=3;r++) { for(c=0;c<3;c++) { printf("\n enter the value="); scanf("%d%d",&a[r][c],&b[r][c]); } } printf("\n first matrix=\n"); for(r=0;r<=3;r++) { for(c=0;c<3;c++) { printf("%d\t",a[r][c]); } printf("\n"); } printf("\n scond matrix=\n"); for(r=0;r<=3;r++) { for(c=0;c<3;c++) {printf("%d\t",b[r][c]); } printf("\n"); } printf("\n sum of given matrix=\n"); for(r=0;r<=3;r++) { for(c=0;c<3;c++) { c[r][c]=a[r][c]+b[r][c]; printf("%d\t",c[r][c]); } printf("\n"); } getch(); }
If you're factoring it, it's c(c + 3) c = 0, -3
3 qt = c.
The mallard duck will let the gasses combust and fart to scare the predators away. If it doesn't scare them then they yell YOLO and die. C=3 C=3 C=3 C=3 C=3