If you're factoring it, it's c(c + 3)
c = 0, -3
4a + 3c - 2b - c + a - b = 5a - 3b + 2c
4c+2 = 3c+9 4c-3c = 9-2 c = 7
3c+6=18 3c+6-6=18-6 3c=12 3c÷3=12÷3 c=4
17-3= 4c+3c c=2
(c + 3)(c^2 - 3c + 9)
c = 4, c squared = 16, 3c squared = 48, 48 + 9 = 57.
No, 3c ( c ) = 4c
3c(squared)-17c-6 = 0 (3c+1)(c-6) = 0 c= negative one third or positive 6
3c
(3c +15)/(c2 - 5) + c/(c + 5)= (3c + 15)/(c - 5)(c + 5) + c/(c + 5)= (3c + 15)/(c - 5)(c + 5) + [c(c - 5)/(c + 5)(c - 5)(since the common denominator is (c + 5)(c - 5)= (3c + 15)/(c - 5)(c + 5) + (c2 - 5c)/(c + 5)(c - 5)= (3c + 15 + c2 - 5c)/(c - 5)(c + 5)= (c2 - 2c + 15)/(c - 5)(c + 5)= [(c - 5)(c + 3)]/(c - 5)(c + 5) (simplify)= (c + 3)/(c + 5)
4a + 3c - 2b - c + a - b = 5a - 3b + 2c
6c.
4c+2 = 3c+9 4c-3c = 9-2 c = 7
In its simplest form, the expression "c plus c plus c" can be simplified by combining like terms. Since there are three instances of "c," it can be expressed as 3c. Thus, the simplest form is 3c.
9c is.
If: 3c = 6Then: c = 2
2c + 4 - 3c = -9 + c + 5 -c + 4 = c - 4 -2c = -8 2c = 8 c = 4