If you're factoring it, it's c(c + 3)
c = 0, -3
4a + 3c - 2b - c + a - b = 5a - 3b + 2c
4c+2 = 3c+9 4c-3c = 9-2 c = 7
3c+6=18 3c+6-6=18-6 3c=12 3c÷3=12÷3 c=4
17-3= 4c+3c c=2
(c + 3)(c^2 - 3c + 9)
c = 4, c squared = 16, 3c squared = 48, 48 + 9 = 57.
No, 3c ( c ) = 4c
3c^(2) -17c - 6 Factors to ( 3c + 1)(c - 6 ) NB When you apply FOIL to the bracketed terms. F ; 3c X c = 3c^(2) O ; 3c X -6 = -18c I ; 1 X c = c L ; 1 x -6 = -6 Collecting 'like' terms 3c^(2) - 18c + c - 6 3c^(2) - 17c - 6 ( As before).
3c
(3c +15)/(c2 - 5) + c/(c + 5)= (3c + 15)/(c - 5)(c + 5) + c/(c + 5)= (3c + 15)/(c - 5)(c + 5) + [c(c - 5)/(c + 5)(c - 5)(since the common denominator is (c + 5)(c - 5)= (3c + 15)/(c - 5)(c + 5) + (c2 - 5c)/(c + 5)(c - 5)= (3c + 15 + c2 - 5c)/(c - 5)(c + 5)= (c2 - 2c + 15)/(c - 5)(c + 5)= [(c - 5)(c + 3)]/(c - 5)(c + 5) (simplify)= (c + 3)/(c + 5)
4a + 3c - 2b - c + a - b = 5a - 3b + 2c
6c.
4c+2 = 3c+9 4c-3c = 9-2 c = 7
In its simplest form, the expression "c plus c plus c" can be simplified by combining like terms. Since there are three instances of "c," it can be expressed as 3c. Thus, the simplest form is 3c.
9c is.
If: 3c = 6Then: c = 2
2c + 4 - 3c = -9 + c + 5 -c + 4 = c - 4 -2c = -8 2c = 8 c = 4