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Asuming that the F1 generation is heterozygous for a single trait and that the F2 cross is of 2 F1 offspring. Ex. Aa X Aa the phenotypic ratio is 3:1 dominant to recessive. The genotypic ratio is 1:2:1 AA:Aa:aa.
The genotypic ratio of a cross of Aa and Aa is: one AA, one aa, and two Aa. Or 1:2:1
The two are very different....
Your answer is A
You can't be sure to get the 50/50 ratio of heads and tails. Each time will be a trial & error.
Because in heterozygotes, both alleles are transcribed and translated.
becouse you touch yourself at night.
If both parents were Dd, they would both be heterozygous for a particular trait. The phenotypic ratio of their offspring would likely be 1 dominant : 2 heterozygous : 1 recessive. This is because the dominant allele masks the recessive allele, resulting in a 3:1 ratio.
A pretty bow
The phenotypic ratio of 2 hybrids would be 3:1 while the genotypic would be 1:2:1. ChaCha on!
Asuming that the F1 generation is heterozygous for a single trait and that the F2 cross is of 2 F1 offspring. Ex. Aa X Aa the phenotypic ratio is 3:1 dominant to recessive. The genotypic ratio is 1:2:1 AA:Aa:aa.
A monohybrid ratio refers to the genotypic and phenotypic ratio seen in the offspring of a genetic cross involving only one trait. For example, in a monohybrid cross between two heterozygous individuals (Aa x Aa), the genotypic ratio among the offspring would be 1:2:1 for AA:Aa:aa, and the phenotypic ratio would be 3:1 for the dominant trait to the recessive trait.
Asuming that the F1 generation is heterozygous for a single trait and that the F2 cross is of 2 F1 offspring. Ex. Aa X Aa the phenotypic ratio is 3:1 dominant to recessive. The genotypic ratio is 1:2:1 AA:Aa:aa.
The phenotypic ratio expected from a monohybrid cross between heterozygotes is 3:1 (assuming complete dominance), with the genotypic ratio being 1:2:1. So, using tall = T, short = t and R = red, r = white as an example. A monohybrid cross of Tt X Tt would be expected to produce 3 tall plants and 1 short plant (phenotypic ratio 3:1), which would be 1 TT, 2 Tt and 1 tt (genotypic ratio 1:2:1). A dihybrid cross of heterozygotes is expected to produce a phenotypic ratio of 9:3:3:1. So the cross of TtRr X TtRr would be epected to have: 9 tall red, 3 tall white, 3 short red and 1 short white (phenotypic ratio) This is because each parent has 4 possible combinations of gametes (TR, Tr, tR and tr). There are therefore 16 combinations of gametes, providing a 9:3:3:1 phenotypic ratio. Both of these are probably best visualised using a punnett square (see link below).
The phenotypic ratio resulting from a dihybrid cross showing independent assortment is expected to be 9:3:3:1. This ratio is obtained when two heterozygous individuals are crossed for two traits that are independently inherited. The ratio represents the different combinations of phenotypes that can arise from the cross.
A genotypic -ratio reflects the genetic configuration of an individual in the population. Several genotypes are possible in a phenotype and the ratio in which the genotypes segregate in a given phenotype is known as its genotypic ratio.
1:1:1:1:1:1:1:1 ratio is the expected outcome of a heterozygous (BbGgCc) and a homozygous recessive (bbggcc) cross.