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When you find an indefinite integral of a function (ie, the integral of a function without integration limits) you are actually finding the antiderivative of that function. In other words, you are finding the function whose derivative is the function 'inside' the integral sign. Recall that the derivative of a constant is zero. The point here is that you add the 'c' to acknowledge the fact that when the derivative of the result of your integration effort is taken to get the original function it could, or would, have been followed by some unknown constant value that disappeared upon differentiation. That constant is denoted by the 'c'.

Q: Why does you put plus c after integration?

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Assuming integration is with respect to a variable, x, the answer is 34x + c where c is the constant of integration.

It is cosh(x) + c where c is a constant of integration.

2

Put their names into the parameter-list.

b+b+b+c+c+c+c =3b+4c

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Assuming integration is with respect to a variable, x, the answer is 34x + c where c is the constant of integration.

It is cosh(x) + c where c is a constant of integration.

There are a lot of rules for integration! Plus a lot of techniques! Here is the power rule as a simple example. int[Xn dx] = (Xn + 1)/(n + 1) + C ( n does not equal - 1 )

The anti-derivative of X2 plus X is the same as the anti-derivative of X2 plus the anti-derivative of X. The anti derivative of X2 is X3/3 plus an integration constant C1 The anti derivative of X is X2/2 plus an integration constant C2 So the anti-derivative of X2+X is (X3/3)+(X2/2)+C1+C2 The constants can be combined and the fraction can combined by using a common denominator leaving (2X3/6)+(3X2/6)+C X2/6 can be factored out leaving (X2/6)(2X+3)+C Hope that helps

2

Put their names into the parameter-list.

cobolbasicc++

-cos x + C

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b+b+b+c+c+c+c =3b+4c

c + c + 2c + c + c = 6c

b + b + b + c + c + c + c = 3b + 4c