math
There is no "power" operator in C or C++. You need to the use the math library function pow().
Assuming integration is with respect to a variable, x, the answer is 34x + c where c is the constant of integration.
It is cosh(x) + c where c is a constant of integration.
6
math
Not without learning and practising.
A + B + C
There is no "power" operator in C or C++. You need to the use the math library function pow().
Assuming integration is with respect to a variable, x, the answer is 34x + c where c is the constant of integration.
It is cosh(x) + c where c is a constant of integration.
6
how n c c marks are added in plus two?
There are a lot of rules for integration! Plus a lot of techniques! Here is the power rule as a simple example. int[Xn dx] = (Xn + 1)/(n + 1) + C ( n does not equal - 1 )
Simply because they're different languages, C++ has a few more added components to it. If they were the same they would both be C wouldn't they?
The integral of ln(2) is a constant multiple of x times the natural logarithm of 2, plus a constant of integration. In other words, the integral of ln(2) with respect to x is x * ln(2) + C, where C is the constant of integration. This integral represents the area under the curve of the natural logarithm of 2 function with respect to x.
The anti-derivative of X2 plus X is the same as the anti-derivative of X2 plus the anti-derivative of X. The anti derivative of X2 is X3/3 plus an integration constant C1 The anti derivative of X is X2/2 plus an integration constant C2 So the anti-derivative of X2+X is (X3/3)+(X2/2)+C1+C2 The constants can be combined and the fraction can combined by using a common denominator leaving (2X3/6)+(3X2/6)+C X2/6 can be factored out leaving (X2/6)(2X+3)+C Hope that helps