The "+ C" in integration represents the constant of integration, which accounts for the fact that indefinite integrals can produce an infinite number of antiderivatives. When you integrate a function, you are essentially finding all functions whose derivative is the original function; since differentiating a constant results in zero, any constant added to an antiderivative will also yield the same derivative. Thus, including "+ C" ensures that all possible solutions are represented.
Assuming integration is with respect to a variable, x, the answer is 34x + c where c is the constant of integration.
It is cosh(x) + c where c is a constant of integration.
The "+ C" added in integration represents the constant of integration, which accounts for the fact that the process of integration determines a family of functions that differ only by a constant. Since the derivative of a constant is zero, any constant value could have been present in the original function before differentiation. Therefore, including "+ C" ensures that all potential antiderivatives are represented.
When you find an indefinite integral of a function (ie, the integral of a function without integration limits) you are actually finding the antiderivative of that function. In other words, you are finding the function whose derivative is the function 'inside' the integral sign. Recall that the derivative of a constant is zero. The point here is that you add the 'c' to acknowledge the fact that when the derivative of the result of your integration effort is taken to get the original function it could, or would, have been followed by some unknown constant value that disappeared upon differentiation. That constant is denoted by the 'c'.
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In C and in C++, the ++ operator means to increment. C++ was intended to be the next version, i.e. the incremental next step, of C, hence the use of the ++ operator.
Assuming integration is with respect to a variable, x, the answer is 34x + c where c is the constant of integration.
It is cosh(x) + c where c is a constant of integration.
all preprocessor directives start with #(hash) symbol in both c & c++
The "+ C" added in integration represents the constant of integration, which accounts for the fact that the process of integration determines a family of functions that differ only by a constant. Since the derivative of a constant is zero, any constant value could have been present in the original function before differentiation. Therefore, including "+ C" ensures that all potential antiderivatives are represented.
When you find an indefinite integral of a function (ie, the integral of a function without integration limits) you are actually finding the antiderivative of that function. In other words, you are finding the function whose derivative is the function 'inside' the integral sign. Recall that the derivative of a constant is zero. The point here is that you add the 'c' to acknowledge the fact that when the derivative of the result of your integration effort is taken to get the original function it could, or would, have been followed by some unknown constant value that disappeared upon differentiation. That constant is denoted by the 'c'.
There are a lot of rules for integration! Plus a lot of techniques! Here is the power rule as a simple example. int[Xn dx] = (Xn + 1)/(n + 1) + C ( n does not equal - 1 )
The anti-derivative of X2 plus X is the same as the anti-derivative of X2 plus the anti-derivative of X. The anti derivative of X2 is X3/3 plus an integration constant C1 The anti derivative of X is X2/2 plus an integration constant C2 So the anti-derivative of X2+X is (X3/3)+(X2/2)+C1+C2 The constants can be combined and the fraction can combined by using a common denominator leaving (2X3/6)+(3X2/6)+C X2/6 can be factored out leaving (X2/6)(2X+3)+C Hope that helps
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-cos x + C
When you see this sign: + plus add plus add ++++++++ , but not when you see : A+, B+, C+, D+. That is your grade. By: super answerer
b+b+b+c+c+c+c =3b+4c