% cannot be a reminder if the divisor is 5, so the question is based on an error.
The largest possible number for a remainder is 1 less than the number of the divisor, so it is 5.
The greatest remainder when dividing by 5 is 4. This is because when a number is divided by 5, the possible remainders are 0, 1, 2, 3, and 4. Since 4 is the highest value in this set, it is the greatest remainder one can obtain when using 5 as the divisor.
'5'
5
If it is divided by a fraction or a decimal. Like 1/5 or .986
5
The largest possible number for a remainder is 1 less than the number of the divisor, so it is 5.
Well, darling, when you divide any number by 5, the largest remainder you can get is 4. Why? Because when you divide by 5, the remainders can only be 0, 1, 2, 3, or 4. So, if you wanna keep it simple and sassy, the largest remainder with a divisor of 5 is 4.
Yes, provided the divisor is greater than 5.
It is not possible to answer this since the divisor is unknown.
The divisor is 9. quotient x divisor + remainder = dividend ⇒ quotient x divisor = dividend - remainder ⇒ divisor = (dividend - remainder) ÷ quotient = (53 - 8) ÷ 5 = 45 ÷ 5 = 9
The greatest remainder when dividing by a number is always one less than that number. Therefore, for the divisors 3, 8, and 5, the greatest remainders would be 2 (for 3), 7 (for 8), and 4 (for 5). Among these, the largest remainder is 7, which corresponds to the divisor 8.
'5'
5. The remainder will never be more than the divisor.
4
5
If it is divided by a fraction or a decimal. Like 1/5 or .986