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Q: With the tailwind a jet flew 2000 miles in 4 hours the jets return trip against the same wind required 5 hours?

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Let the speed of the airplane in still air be represented by V.Velocity = Distance Ã· Time, thus Distance = Velocity x Time.D = 4(V + 20) = 5(V - 20), then 4V + 80 = 5V - 100 : V = 180 kphThe speed in still air is 180kph

275 km/hr

275 km/hr

15 miles

20 hours a month

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Let the speed of the airplane in still air be represented by V.Velocity = Distance Ã· Time, thus Distance = Velocity x Time.D = 4(V + 20) = 5(V - 20), then 4V + 80 = 5V - 100 : V = 180 kphThe speed in still air is 180kph

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OK so I'm getting on a flight from Denver to Dubai with a stopover at London Heathrow. On the way a to London a Tailwind was pushing the aircraft. But on the way from a london to Dubai a sandstorm occured pushing us back. From Colorado to London it was 10 hours 30 minutes. From London to Dubai it took 8 Hours. Find the Speed of the Aircraft and the Speed of the Tailwind and the Sandstorm's headwind.

Using the Australian time zone without change, it would take about 18 hours or so if the plain had a good tailwind.

The duration of Return to Me is 1.92 hours.

35 mph