Q: Write the equation of a line in slope intercept form that has a slope of 2 and contains the point 1 AND 1?

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It is: y-7 = 2(x-3) => y = 2x+1

As a straight line equation: y = -3x+18 in slope intercept form

y=2x+1

y=3x-3

y=mx+b, right? So, b is the height of the y-intercept that you already have. M is the slope, rise over run. The slope is the same at all part of a line. You take the distance up from the y-intercept to the point and divide by the distance right from the y-intercept to the point. Replace m with that and you have the equation.

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Write the equation in slope-intercept form of the line that has a slope of 2 and contains the point (1, 1).

The answe iss..... 6

y = 2x - 1

y=2x+1

It is: y = 2x-6

y-9 = 3(x-4) y = 3x-3 in slope intercept form

No, you need either two points, one point and a slope, one point and a y-intercept, or a y-intercept an a slope. You can also write the equation of a line with an equation of another line but you would have to know if it is parallel or perpendicular.

Write the equation of a line in slope-intercept form that has a slope of -2 and passes through the point (2, -8).

It is: y-7 = 2(x-3) => y = 2x+1

As a straight line equation: y = -3x+18 in slope intercept form

plug in the slope(m) and coordinates (x,y) into the slope-intercept formula & solve for b.slope-intercept formula: y=mx+b

y- -5 = -3(x-4) y = -3x+12-5 y = -3x+7 in slope intercept form