slope intercept form is y = mx + b
m is slope, b is y-intercept.
you know slope(m=6) and the point (1, 1)
then, put them into the equation.
y = mx + b
1 = 6*1 + b
1 = 6 + b
1 - 6 = 6 + b - 6
b = -5
now you know slope and y-intercept. so, the answer is
y = 6x -5
if you are still confused, i want you to follow the link below.
http://www.brightstorm.com/d/math/s/algebra/u/linear-equations-and-their-graphs/t/writing-equations-in-slope-intercept-form
The equation is (y - 1) = 2(x - 1) or, y = 2x - 1
As a straight line equation: y = -3x+18 in slope intercept form
It is: y-7 = 2(x-3) => y = 2x+1
y=2x+1
y=3x-3
Write the equation in slope-intercept form of the line that has a slope of 2 and contains the point (1, 1).
The answe iss..... 6
y=2x+1
y = 2x - 1
It is: y = 2x-6
y-9 = 3(x-4) y = 3x-3 in slope intercept form
No, you need either two points, one point and a slope, one point and a y-intercept, or a y-intercept an a slope. You can also write the equation of a line with an equation of another line but you would have to know if it is parallel or perpendicular.
The equation is (y - 1) = 2(x - 1) or, y = 2x - 1
Write the equation of a line in slope-intercept form that has a slope of -2 and passes through the point (2, -8).
As a straight line equation: y = -3x+18 in slope intercept form
It is: y-7 = 2(x-3) => y = 2x+1
plug in the slope(m) and coordinates (x,y) into the slope-intercept formula & solve for b.slope-intercept formula: y=mx+b