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x2 + 4x - 12 = 0 so (x+6)*(x-2) = 0 so x = -6 or x = 2


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To solve the quadratic equation x2 + 4x - 12 = 0, you can use two different methods:

1: Reduce it to its factors:

x2 + 4x - 12 = 0 is the same as (x + 6)(x - 2) = 0. But this can only be correct if one of the factors is zero which only happens when x = -6 or x = 2. That is the solution.

2: Use the quadratic solution formula:

x2 + 4x - 12 = 0 is of the form ax2 + bx + c = 0 with a = 1, b = 4, and c = -12.

Substitute these values into the formula
x = (-b ± sqrt(b2 - 4ac)) / 2a and you get
x = (-4 ± sqrt(16 - (-48)) / 2
= (-4 ±sqrt(64)) / 2
= (-4 + 8) / 2 or (-4 - 8) / 2
= 4 / 2 or -12 / 2
so x = 2 or x = -6
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