x2 + 7x = -2X2+6
3x2 + 7x -6 = 0
(3x-2)(x+3) = 0
Either 3x-2=0
or x+3=0
Either x=2/3
or x=-3
Plug the numbers into the original equation to check.
(2/3)2 + 7(2/3) = -2(2/3)2 +6
4/9 + 14/3 = -8/9 + 6
4/9 + 42/9 + 8/9 - 54/9 = 0
0=0
That one checks out. Let's try the second one.
(-3)2 + 7(-3) = -2(-3)2 + 6
9 -21 = -18 + 6
9 -21 +18 -6 = 0
0=0
The second one checks out also; so both answers are good.
Answer: x = 2/3 or x = -3
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x2 + 7x = 2x2 + 6 x2 - 2x2 + 7x = 6 -x2 +7x - 6 = 0 or alternatively x2 - 7x + 6 = 0
6x3 - x2 + 17 = 2x2 + 47 6x3 - x2 - 2x2 = 47 - 17 x2(6x - 1 - 2) = 30 this is the simplest factorisation.
x2+7x+3 = 0 Using the quadratic equation formula the solutions are:- x = -6.541381265 or x = -0.4586187349
Assuming that what you're looking for is the values of x: x2 + 7x = 8 x2 + 7x - 8 = 0 (x + 8)(x - 1) = 0 x is equal to either -8 or 1.
x2-7x+12 = 0 (x-3)(x-4) = 0x=3,4