0
x2 + 7x = -2X2+6
3x2 + 7x -6 = 0
(3x-2)(x+3) = 0
Either 3x-2=0
or x+3=0
Either x=2/3
or x=-3
Plug the numbers into the original equation to check.
(2/3)2 + 7(2/3) = -2(2/3)2 +6
4/9 + 14/3 = -8/9 + 6
4/9 + 42/9 + 8/9 - 54/9 = 0
0=0
That one checks out. Let's try the second one.
(-3)2 + 7(-3) = -2(-3)2 + 6
9 -21 = -18 + 6
9 -21 +18 -6 = 0
0=0
The second one checks out also; so both answers are good.
Answer: x = 2/3 or x = -3
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What is x2 plus 7x equals - 2x2 plus 6 in the form ax2 bx c equals 0?
x2 + 7x = 2x2 + 6 x2 - 2x2 + 7x = 6 -x2 +7x - 6 = 0 or alternatively x2 - 7x + 6 = 0
How do you factor 6x3-x2 plus 17 equals 2x2 plus 47?
6x3 - x2 + 17 = 2x2 + 47 6x3 - x2 - 2x2 = 47 - 17 x2(6x - 1 - 2) = 30 this is the simplest factorisation.
What are the solutions of x2 plus 7x plus 3 equals 0?
x2+7x+3 = 0 Using the quadratic equation formula the solutions are:- x = -6.541381265 or x = -0.4586187349
X2 plus 7x equals 8?
Assuming that what you're looking for is the values of x: x2 + 7x = 8 x2 + 7x - 8 = 0 (x + 8)(x - 1) = 0 x is equal to either -8 or 1.
2x2 plus 42 equals x2 plus 13x?
This is a quadratic equation question which will have two answers: 2x2+42 = x2+13x 2x2-x2-13x+42 = 0 x2-13x+42 = 0 Factorising the equation gives you: (x-6)(x-7) = 0 Therefore: x = 6 or x = 7
What is x2 plus 7x equals - 2x2 plus 6 in the form ax2 bx c equals 0?
x2 + 7x = 2x2 + 6 x2 - 2x2 + 7x = 6 -x2 +7x - 6 = 0 or alternatively x2 - 7x + 6 = 0
X2 plus 7x equals -2x2 plus 6?
x2+7x=-2x2+6 3x2+7x-6=0 (3x-2)(x+3)=0 3x-2=0 or x+3=0 x=2/3 or x=-3
What does x2 plus x2 equals?
x2 + x2 = 2x2
X2 plus 7x plus 12 equals 0?
x2+7x+12=0 x2+7x=-12 x+Sqaure Root of 7x= 2(SQ Root Symbol)3
X2 plus 7x plus 10 equals?
The value of x2+7x+10 depends on the value of X. If x=1, then x2+7x+10 = 18 If x=2, then x2+7x+10 = 28 If x=3, then x2+7x+10 = 40 and so forth
How do you factor 6x3-x2 plus 17 equals 2x2 plus 47?
6x3 - x2 + 17 = 2x2 + 47 6x3 - x2 - 2x2 = 47 - 17 x2(6x - 1 - 2) = 30 this is the simplest factorisation.
X2 plus 7x plus 9 equals 3?
x2 + 7x + 9 = 3 ∴ x2 + 7x + 6 = 0 ∴ (x + 6)(x + 1) = 0 ∴ x ∈ {-6, -1}
What are the points of intersection of the curves y equals x2 -7x plus 8 and y equals -x2 plus 9x -6 showing work?
If: y = x2-7x+8 and y = -x2+9x-6 Then: x2-7x+8 = -x2+9x-6 So: 2x2-16x+14 = 0 => x2-8x+7 = 0 Therefore: x = 1 and x = 7 By substitution: x =1, y = 2 and x = 7, y = 8 Points of intersection: (1, 2) and (7, 8)
Maxz equals 2x1 plus 2x2 stc 5x1 plus 3x2 equals 8 x1 plus 2x2 equals 4 x1 x2 equals 0 and integerssolve by ipp?
3
How do you solve x2 plus 7x plus 12?
x2+7x+12
What are the solutions of x2 plus 7x plus 3 equals 0?
x2+7x+3 = 0 Using the quadratic equation formula the solutions are:- x = -6.541381265 or x = -0.4586187349
What is X2 plus X2?
x2 + x2 = 2x2
